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Rzqust [24]
3 years ago
13

If a 5kg ball is traveling at 20 m/s and it’s stopped in 4s, what’s the impulse on the ball?

Physics
1 answer:
Anna [14]3 years ago
4 0
FT=MV

F(4)=(5)(20)

F= 100/4

F= 25 N
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muminat

Answer:

resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.

Explanation:

assume that the ship started moving from A to B (north at 50km/hr for 2 hours) so the covered distance will be: 50*2 = 100 km

then it moves from B to C so the covered distance will be: 3*60 = 180 km

using Pythagoras, we get the resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.

8 0
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4 0
3 years ago
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Explanation:

It is given that,

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So, \dfrac{W_A}{W_N}=\dfrac{mg-\dfrac{mv^2}{r}}{mg}

\dfrac{W_A}{W_N}=\dfrac{g-\dfrac{v^2}{r}}{g}

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or

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3 years ago
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