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3 years ago

How to solve x using logarithms

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

6 0

Step-by-step explanation:

$\frac{1}{2} log(x) + log(4) = 2$

then

$log( {x}^{ \frac{1}{2} } ) + log(4) = 2 \\ log(4 \sqrt{x} ) = 2 \\ 4 \sqrt{x} = {10}^{2} = 100 \\ \sqrt{x} = 25 \\ x = {25}^{2} = 625$

I don't know if your Log is natural logarithm then

$4 \sqrt{x} = {e}^{2} \\ \sqrt{x} = \frac{e ^{2} }{4} \\ x = \frac{ {e}^{4} }{16}$

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ELEN [110]

29.4H is the equation

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Radio tower had a special on rechargeable batteries. It sold AA for $1 and AAA for $0.75. It sold 42 batteries on a single day a

PIT_PIT [208]

AA = $1
AAA= $0.75

AA + AAA = 42

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AA + AAA = 42
AA + AAA-AAA= 42- AAA
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Check
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3 years ago

Which statement is true about the domain of y = 3(2^-x)? Explain.

SVEN [57.7K]

We want to determine the domain of ${y=3 \cdot 2^{-x}=3 \cdot ({2^{-1}})^x=3 \cdot ({ \frac{1}{2}})^x$

any function of the form $y=f(x)=a \cdot b^x$ is called an "exponential function",
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3 years ago

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Answer:

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3 years ago

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tino4ka555 [31]

Answer:

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3 years ago

Read 2 more answers