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lana [24]
3 years ago
15

X/3 +17 less than or equal to 15

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

x \leqslant  - 6

x/3+17is less than or equal to 15

x/3is less than or equal to 15-17

xis less than or equal to -6

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what is the answer to the volleyball team at blue point high school has saved $680 and the team plans to spend no more then that
zloy xaker [14]

Answer:

6 x + 23 y  < $ 680  represents the combinations of x balls and y nets that can be purchased.

Step-by-step explanation:

The number of balls than can be purchased  = x

The number of nets than can be purchased  = y

Total savings  = $ 680

Now, the cost of 1 ball =$6

So, the cost of x balls = x ( cost of 1 ball) = x ( $6)  = 6 x

Also, the cost of 1 net =$23

So, the cost of y nets = y ( cost of 1 net = y ( $23)  = 23 y

So, the total amount spent on x balls  and y nets

= Amount spent on x balls + Amount on y nets

=  6 x + 23 y

Also, the saved amount is $680

⇒<u> 6 x + 23 y  < $ 680</u>

Hence, 6 x + 23 y  < $ 680  represents the combinations of x balls and y nets that can be purchased.

4 0
3 years ago
How do I find the values of x and y?
zepelin [54]
All 3 angles =180...
3 0
3 years ago
Wich equation shows y + 1/5 = 3x in standard form
Katen [24]

15x - 5y = 1 it's B in standard form



4 0
3 years ago
A researcher asks 4 people if they like to watch thriller movies, and 3 people say they do. Explain why the following statement
serg [7]
This sample size it too small.  The larger the sample size, the more likely the data will be true to what the question is asking.  A larger sample size brings more precision to the question that is being asked.
5 0
3 years ago
What are the missing parts that correctly complete the proof
bonufazy [111]

Answer:

2. \overline{AX}\cong \overline{BX}

3. PX \perp AB - definition of perpendicular

4. \angle PXA \cong \angle PXB - all right angles are congruent

6. \triangle AXP\cong \triangle BXP

7. \overline{PA} \cong \overline{PB}

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2.\overline{AX}\cong \overline{BX} - definition of bisector

3. PX \perp AB - definition of perpendicular

4.  \angle PXA \cong \angle PXB - all right angles are congruent

5. \overline{PX} \cong \overline{PX} - reflexive property of congruence

6. \triangle AXP\cong \triangle BXP - SAS congruency postulate

7. \overline{PA} \cong \overline{PB} - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0
3 years ago
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