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belka [17]
3 years ago
11

Is it possible to trisect any angle using only a compass and a straight edge

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0

Answer:

NO , an angle is not trisected using only a compass and a straight  edge.

Step-by-step explanation:

We are given two tools a compass and a straight edge

We need to tell if an angle is trisected using them or not.

Answer is NO , an angle is not trisected using only a compass and a straight  edge.

When we draw a semicircle by point pointer of compass at vertex of angle and then draw a line using points we get when semicircle intersects the arms of the angle. We get angle Bisection.

We again try to bisect we get four equal angles not Three.

So It is impossible to make odd numbers of equal angles from a given angle using a compass and a straight edge.

xeze [42]3 years ago
4 0

Hello from MrBillDoesMath!

Answer:

No. That problem cited is one of 3 great unsolved problems of antiquity. See  https://en.wikipedia.org/wiki/Angle_trisection for details.


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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There are two negative roots to the provided polynomial function

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n

We have a polynomial function:

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

\rm f(x) =\left(x+1\right)\left(x^6-x^5+x^4-3x^3+3x^2+4x-2\right)

Using the zero product property:

\rm \left x+1\right = 0 \ \ \ or \left x^6-x^5+x^4-3x^3+3x^2+4x-2\right = 0

After solving:

x = -1, x = -0.853, and x = 0.418 (using the graph method)

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Learn more about Polynomial here:

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Step-by-step explanation:

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