Answer:
The probability of rolling a sum greater than 1 when rolling two fair numbered cube is 1 or 36/36.
Step-by-step explanation:
There is no 1 as a sum when rolling two fair numbered cubes, so all the sums will be greater than 1.
Step-by-step explanation:
Lets first find the remainder when p(x) is divided by x-2
p(2)=2(2)³+b(2)²+3(2)-5
p(2)=16+4b+6-5
p(2)=4b+17
Now let's find the remainder when q(x) is divided by x-2
q(2)=(2)³+(2)²-4(2)-b
q(2)=8+4-8-b
q(2)=4-b
Now let's equate both of them
4b+17=4-b
4b+b=4-17
5b=-13
b=-13/5 as required
Answer:
No Solution
Step-by-step explanation:
Answer:
first off here are the things you need to know:
She parked her car 4 levels below the street
so let's make that 4
and he doctor's office is at the fifth level of the building which makes it 5
so; 4+5=9 meaning she ride the elevator 9 levels
It must be 6 since the length sides r doubled and it's similar