All categories

3 years ago

Escribe, en los siguientes cuadros, los conceptos que correspondan

Computers and Technology

1 answer:

Fofino [41]3 years ago

3 0

Answer:

Débito o debe Crédito o haber

Préstamo de la cooperativa Efectivo

Gasto de arriendo Cuentas por cobrar

Cuentas por pagar Documentos por cobrar

Gasto de publicidad Capital social

Hipoteca por pagar Ventas

Intereses pagados Bancos (en el caso de cobros a través de bancos)

Bancos (en el caso que deba productos bancarios)

Explanation:

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3 years ago

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2 years ago

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Write a function that receives a StaticArray where the elements are already in sorted order, and returns a new StaticArray with

Allisa [31]

The code that remove duplicate is as follows:

def remove_duplicate(mylist):

mylist = list(dict.fromkeys(mylist))

return mylist

print(remove_duplicate([1, 1, 2, 3, 3, 5, 6, 7]))

<h3>Code explanation</h3>

The code is written in python.

we defined a function named "remove_duplicate" and it accept the parameter "mylist".
The variable "mylist" is used to store the new value after the duplicate vallues has been removed.
Then, wed returned mylist.
Finally, we call the function with the print statement . The function takes the required parameter.

learn more on python here: brainly.com/question/21126936

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2 years ago

again assume that each of the resistors in the circuit shown above has a resistance value of 100k(question in the picture above)

Svetllana [295]

Statement A is true. R4 is not part of the circuit since it has one terminal not connected. The other resistors are in series, so the same current flows through them. Hence they will dissipate equal power.

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3 years ago

Lists and Procedures Pseudocode Practice For each situation, provide a pseudocoded algorithm that would accomplish the task. Mak

Andrei [34K]

Answer:

The pseudocoded algorithm is as follows:

Procedure sumOdd(lotsOfNumbers):

oddSum = 0

len = length(lotsOfNumbers)

for i = 0 to len - 1

if lotsOfNumbers[i] Mod 2 != 0:

OddSum = OddSum + lotsOfNumbers[i]

Print(OddSum)

Explanation:

This defines the procedure

Procedure sumOdd(lotsOfNumbers):

This initializes the oddSum to 0

oddSum = 0

This calculates the length of the list

len = length(lotsOfNumbers)

This iterates through the list

for i = 0 to len-1

This checks if current list item is odd

if lotsOfNumbers[i] Mod 2 != 0:

If yes, the number is added to OddSum

OddSum = OddSum + lotsOfNumbers[i]

This prints the calculated sum

Print(OddSum)

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3 years ago