the value ax^2 + bx is 5 when x=1, and is equal to 0 when x=1.what are the values of a and b. explain how u arrived at your answ
er
1 answer:
Answer: a = 1.25, b = 2.5, c = 1.25
Step-by-step explanation:
Use vertex form and substitute a point into it (1, 5)
5 = a(1 + 1)^2 + 0
5 = a(2)^2 + 0
5 = 4a
a = 5/4
y = 5/4 (x + 1)^2
y = 5/4 (x^2 + 2x + 1)
1.25 x^2 + 2.5x + 5/4
Is there a "c" value otherwise it's not possible
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Answer: D) 18
Step-by-step explanation:
6 - x = -12
Subtract 6 from both sides.
-x = -18
Divide by -1 on both sides so as to isolate x.
x = 18
I know m=2.25 and n=8.6 but I don't know about q.
The one above the one you have now
Let, the length = l
Width = l/2
Area = l * w = l * l/2 = l²/2
So, Your Final Answer would be A = l²/2
Hope this helps!
10*3=30
30*3=90
90*3=270
270*3=810
or
10*3^1=30
10*3^2=90
10*3^3=270
10*3^4=810
the next two terms of this sequence are 270 and 810.
