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jasenka [17]
3 years ago
13

the value ax^2 + bx is 5 when x=1, and is equal to 0 when x=1.what are the values of a and b. explain how u arrived at your answ

er
Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Answer: a = 1.25, b = 2.5, c = 1.25

Step-by-step explanation:

Use vertex form and substitute a point into it (1, 5)

5 = a(1 + 1)^2 + 0

5 = a(2)^2 + 0

5 = 4a

a = 5/4

y = 5/4 (x + 1)^2

y = 5/4 (x^2 + 2x + 1)

1.25 x^2 + 2.5x + 5/4

Is there a "c" value otherwise it's not possible

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4 years ago
Which graph shows the solution to this system of inequalities?<br> y&gt;-1/3x+1<br> y&gt;2x-3
Mademuasel [1]

Given:

The system of inequalities is:

y>-\dfrac{1}{3}x+1

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The graph of the given system of inequalities.

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y>-\dfrac{1}{3}x+1

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The related equations are:

y=-\dfrac{1}{3}x+1

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Table of values for the given equations is:

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   0                             1                              -3

   3                             0                              3

Plot (0,1) and (3,0) and connect them by a straight line to get the graph of y=-\dfrac{1}{3}x+1.

Similarly, plot (0,-3) and (3,3) and connect them by a straight line to get the graph of y=2x-3.

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Therefore, the graph of the given system of inequalities is shown below.

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