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creativ13 [48]
3 years ago
15

Classify the number by selecting which set or sets it belongs to.

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

yes sir i can elp you let me just get you a dicktionary

Step-by-step explanation:

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Two more than than 4 times a number is -18
wolverine [178]
-4..................
7 0
3 years ago
Drag each expression to show whether it is equivalent to
Kazeer [188]

Answer:

We need to find which expressions are equivalent to 6(c+6), 6c+6 or neither.

6c+12: We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.

6c+12=+(c+2)

Therefore, this expression is equivalent to neither of the given expressions.

2(3c+3): We just need to apply the distributive property.

2(3c+3)=6c+6

Therefore, this expression is equivalen to 6c+6.

We use the same process to the other expressions.

(6c)+(6\times 6)=6c+36=6(c+6)

3c+6+3c=6c+6

6c+36=6(c+6)

(6+c)+(6+6)=c+18, equivalent to neither.

7 0
3 years ago
x = 5 y = -3 What is the solution to the system of equations? A) (0, 0) B) (5, -3) C) (-5, 3) D) (-3, 5)
Rufina [12.5K]

I think its B because, the formation would be (x,y) so that means (5,-3)

5 0
3 years ago
Select all the values of x from this list that make the inequality <br><br><br> FOR POINTS!
denis23 [38]
The answer would be A D E
8 0
3 years ago
joe has a piggy bank with $8.90 split upon nickels, dimes, and quarters. The piggy bank contains 76 coins in all. The number of
kozerog [31]

Answer:

There are 38 dimes, 22 nickels and 16 quarters.

Step-by-step explanation:

Let n, d and q represent the # of nickels, dimes and quarters respectively.

Then n + d + q = 76

The value of a nickel is $0.05; that of a dime is $0.10, and that of a quarter is $0.25.

Thus, the value of n nickels is $0.05n (and so on).

The total value of the coins is $0.05n + $0.10d + $0.25q = $8.90.

d = n + q allows us to eliminate d.

First, n + d + q = 76 becomes n + (n + q) + q = 76, and second:

$0.05n + $0.10(n + q) + $0.25q = $8.90.  Here we have succeeded in eliminating d from two different equations, and now we have these two different equations in two unknowns (n and q), which is solvable.

Simplifying both equations, we get:

2n + 2q = 76 and

5n + 10n + 10q + 25q = 890, or 15n + 35q = 890

Let's use the substitution method of solving linear equations:

Rewrite 2n  + 2q = 76 as n + q = 38, or n = 38 - q.  Substituting this result into the second equation, we get:

15(38 - q) + 35 q = 890, or

  570 - 15q + 35q = 890, or

   570 + 20 q = 890.  Then 20q = 890 - 570 = 320, and q = 320/20 = 16.

There are 16 quarters.  Thus, the number of nickels is n = 38 - 16 = 22.

Finally, since n + d + q = 76, 22 + d + 16 = 76, or:

22 + d = 60, or d = 60 - 22 = 38.

There are 38 dimes, 22 nickels and 16 quarters.

4 0
3 years ago
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