The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Let's consider adults tickets be a and child tickets be c
so
Roy's purchase
6a+2c=66------1
Elisa's purchase
5a+4c=62-------2
Hence, the system of equations
6a+2c=66------1
5a+4c=62-------2
solving simultaneously
6a+2c=66
5a+4c=62
Also,
12a+4c=132
-5a+4c=62
7a=70
a=$10
put a=70 in 1
6(10)+2c=66
60+2c=66
2c=66-60
2c=6
c=$3
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since by the provided tickmarks WE ≅ ER, and QE ≅ ET, then both triangles are congruent by LL theorem, Leg Leg.
anyhow, since those legs are congruent, their hypotenuses must also be congruents, and we could use the HL theorem as well.
Answer: 12
Step-by-step explanation: I assume you are talking about a triangle in which the Hypotenuse is 15 and leg A is 9
in this case we have to use a reverse pythagorean theorem
the original one is a^ + b^ = c^ then reverse it to get c^ - a ^ = b^
we know that C is 15 and A is 9 so substitute
15^ - 9^ = b^
15 ^ = 225 and 9^ = 81 so substitute again
225 - 81 = b^ then subtract
144 = b^ you know that the square root of 144 is 12 because 12 x 12 = 144
so 12 is the last side
hope this helps mark me brainliest if it did
Answer:
14
Step-by-step explanation:
You take the 400 and you minus 38 you get 362 then u divide that by 25 you get 14.48. I personally would just go with 14
