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Andrej [43]
3 years ago
12

The process by which drug molecules are transformed into simpler products is called? HELP FASTT!!!!​

Chemistry
1 answer:
Ratling [72]3 years ago
8 0
This process is called metabolites!
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Which atom has the lowest(smallest) ionization energy?<br> A. Na<br> B.K<br> C. Me<br> D. Ca
serious [3.7K]
K. Ionization energy increases as you go up and to the right, and k is the furthest left and furthest down
7 0
3 years ago
H
Harman [31]

Answer:c

Explanation: it's easy

7 0
4 years ago
What is the boiling point of a solution made by adding 6.69 g of magnesium chloride to 250.0 g of water?. Use the formula of the
olya-2409 [2.1K]

Answer:

100.432ºC

Explanation:

Ebullioscopy is the elevation of the boiling point of a solvent that has a solute nonvolatile dissolved. The change in the temperature may be calculated by Raoult's law:

ΔT = Kb.W.i

Where <em>ΔT</em> is the temperature change, <em>Kb</em> is the ebullioscopy constant,<em> W</em> is the molality and <em>i</em> is the Van't Hoff factor, which determinates the particles that affect the proper.

The molality is:

W = m1/(M1xm2)

Where <em>m1</em> is the solute mass (in g), <em>M1</em> is the molar mass of the solute, and <em>m2</em> is the mass of the solvent (in kg).

The Van't Hoff factor is the number of final particles divided by the number of initial particles. Magnesium is from froup 2, so it forms the cation Mg⁺², and chlorine ins from group 7 and forms the anion Cl⁻, the salt is MgCl₂ and dissociates:

MgCl₂  → Mg⁺²(aq) + 2Cl⁻(aq)

So, it has 1 particle in initial, and 3 in final (1  Mg⁺² and 2 Cl⁻). So:

i = 3/1 = 3.

The molar mass of MgCl₂ is: 24.3 + 2x35.5 = 95.3 g/mol, m1 = 6.69g, m2 = 0.250 kg, so:

W = 6.69/(95.3x0.250)

W = 0.281 m

Then:

ΔT = 0.512x0.281x3

ΔT = 0.432ºC

The normal boling point of water is 100ºC, so

T - 100 = 0.432

T = 100.432ºC

6 0
3 years ago
Consider molecular, complete ionic, and net ionic equations.
8090 [49]

Explanation:

(a) The molecular equations shows the equation in which all the species of the reactants and the products are in molecules and the net charge is zero.

The complete ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and are represented as ions.

The net ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and do not show the spectator ions which are same in the reactants and the products.

(b) If there is no spectator ions in the reaction, then the complete and the net ionic equations would be identical.

3 0
3 years ago
Determine how many grams of precipitate (solid) will form when 621 g of magnesium
kakasveta [241]

Answer:

2,981g

Explanation:

Firstly, we need to find the number of moles of MgCl that we have by using the formula: mass = No. Moles x Molar Mass, which we can rearrange so that we are solving for no. moles:

No. Moles = mass / Molar Mass

We are given a mass of 621g, and we can calculate the molar mass of MgCl by adding the two molar masses together: 24.31+35.45 = 59.76

Now we can calculate number of moles by substituting these values into the formula:

n = 621 / 59.76

No. moles = 10.4

Now we can use the co-efficients in the formula to tell us how many moles of AgCl will be formed. The coefficient of MgCl is 1, and the coefficient of AgCl is 2. This means that every 1 mol of MgCl will form 2 moles of AgCl. So, to find the no. moles of AgCl, we multiply our no. moles by 2:

10.4 x 2 = 20.8 moles

Finally we convert this back into mass by multiplying the no. moles by the Molar mass of AgCl:

m = 20.8 x (107.87+35.45)

m = 2,981g

8 0
3 years ago
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