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borishaifa [10]
4 years ago
9

Pure metals tend to be weaker and more reactive than an alloy which is a

Chemistry
1 answer:
Alex17521 [72]4 years ago
5 0
Alloys are supposed to give greater strength to metals, which is why gold is mixed with others to make it harder. They have greater strength and are more resistant to erosion.
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QUESTION 5
Elenna [48]

B. 3.77 L is the new volume occupied by the gas.

<u>Explanation:</u>

As per Avogadro's law, which states that if the pressure and temperature held constant, then an equal volume of the gases will occupy an equal number of molecules. It can be written as,

$\frac{V1}{n1} = \frac{V2}{n2}\\

Here, V1, volume of the helium gas = 2.9 L

V2, volume of the additional helium gas in the balloon = ?

n1, moles of helium gas = 0.150 mol

n2, number of moles of additional helium gas = 0.150 + 0.0450 = 0.195 mol

We have to rearrange the equation for V2 as,

V2 = $\frac{V1n2}{n1}

Now Plugin the values as,

V2 = $\frac{2.9 L \times 0.195 mol}{0.150 mol}

  = 3.77 L

So the new volume of the balloon is 3.77 L.

6 0
3 years ago
What is the wavelength of the light emitted that has a frequency of 1.50 x 1013 Hz? 2.5 x 10-21 m 2.0 x 10-5 m 5.0 x 105 m 4.5 x
Inessa05 [86]
V (speed) = f (frequency) ­* y (meant to be lambda) (wavelength)
y = v/f (v is speed of light --3.0*10^8m/s)
y = 3.0*10^8/1.5*10^13
The answer is y = 2.0*10-5.
3 0
3 years ago
Read 2 more answers
How many moles of MgCO3 are in 2.57g of MgCO3?
Sveta_85 [38]

Answer:

0.0305 moles of MgCO₃

Explanation:

In order to solve this problem, we first need to calculate the molecular weight of MgCO₃:

  • MgCO₃ MW = Atomic mass Mg + Atomic mass C + (Atomic mass O)*3
  • MgCO₃ MW = 24.3 + 12 + 16*3 = 84.3 g/mol

Finally we <u>divide the mass by the molecular weight</u>, to calculate the <em>number of moles</em>:

  • 2.57 g MgCO₃ ÷ 84.3 g/mol = 0.0305 moles.
7 0
3 years ago
Which atom in the ground state has five electrons in its outee level and ten electrons in its kernel (1) C (2) Cl (3) Si (4) P
inn [45]
If you use its electronic structure the last number should be a five so something like (2,5), (2,8,5) or (2,8,8,5) etc. 

The elements therefore with 5 as it's final number and 5 on the outer orbit are N, P, As, Sb, Bi, Uup. Therefore with the answers given to you the answer is most likely 4) Phosphorus.  <span />
4 0
3 years ago
5. Balance the following reactions using either the oxidation number method or the half-reaction
stich3 [128]

The balanced reaction equations are;

a) 4 NaClO + H2S → 4 NaCl + H2SO4

b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O

<h3>What is a balanced redox reaction?</h3>

A redox reaction is said to be balanced when the number of electrons gained is equal to the number of electrons lost.

Let us now write the balanced reaction equations one after the other. Thus;

a) 4 NaClO + H2S → 4 NaCl + H2SO4

b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O

Learn more about redox reaction:brainly.com/question/13293425

#SPJ1

7 0
2 years ago
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