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3 years ago

Cone,cube,cylinder, sphere, and/or rectangular prism... my cross sections are sometimes a circle

Mathematics

1 answer:

mina [271]3 years ago

8 0

Answer:

cone , cylinder and sphere

Step-by-step explanation:

these 3 solids {cone , cylinder , sphere} their cross sections are sometimes a circle.

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3 years ago

Which of the following represents the set of integers greater than or equal to -5?

Ann [662]

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3 years ago

Read 2 more answers

Which is the graph of linear inequality 6x+2y>-10

NemiM [27]

For this case we have the following inequality:
$6x + 2y\ \textgreater \ -10
$
The first thing we must do is to graph the linear function:
$6x + 2y = -10
$
Then, we must evaluate ordered pairs in the following way:
(x, y)
The ordered pairs that meet the inequality, will be included as part of the graph.
Therefore, the shaded region contains all the ordered pairs that meet the inequality.
Answer:
See attached image.

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3 years ago

Write an equation in point slope form for the line on the graph

Yakvenalex [24]

Y=mx+b
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3 years ago

Find the slope of the line that passes through (6, 7) and (2, 10). and simplify if needed thx guys.

tekilochka [14]

Answer:

$-\frac{3}{4}$

Step-by-step explanation:

the equation for finding the slope of a line when given two points is $\frac{y_2-y_1}{x_2-x_1}$ , aka the change in y over the change in x.

pick one of your coordinate pairs to be $y_2\\$ and $x_2$ . it doesn't matter which coordinate pair you choose as long as you keep them as $y_2\\$ and $x_2$ . the remaining coordinate pair will be $y_1$ and $x_1$ .

for this example, i'll use (2, 10) for $y_2\\$ and $x_2$ and (6, 7) for $y_1$ and $x_1$ .

**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for $y_2\\$ and 2 for $x_2$ ). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.

first, start by plugging in the y-value from the coordinate pair of your choosing in for $y_2\\$ . since i chose (2, 10) for $y_2\\$ and $x_2$ , i'll plug in 10 for $y_2\\$ .

$\frac{y_2-y_1}{x_2-x_1}$ ⇒ $\frac{10-y_1}{x_2-x_1}$

then plug in the remaining coordinate pair's y-value in for $y_1$ . since the coordinate pair that's left is (6, 7), i will plug in 7 for $y_1$ .

$\frac{y_2-y_1}{x_2-x_1}$ ⇒ $\frac{10-7}{x_2-x_1}$

now i'm going to plug in the x-values. i chose (2, 10) to plug in for $y_2\\$ and $x_2$ , so now i'll plug in 2 for $x_2$ .

$\frac{y_2-y_1}{x_2-x_1}$ ⇒ $\frac{10-7}{2-x_1}$

and all that's left to plug in is the x-value from (6, 7), so i will plug that in for $x_1$ .

$\frac{y_2-y_1}{x_2-x_1}$ ⇒ $\frac{10-7}{2-6}$

after plugging in all the values, you have $\frac{10-7}{2-6}$ .

subtract 10 - 7 as well as 2 - 6.

$\frac{10-7}{2-6}$ ⇒ $\frac{3}{-4}$

$\frac{3}{-4}$ cannot be simplified, therefore the slope of the line is $\frac{3}{-4}$ or $-\frac{3}{4}$ .

i hope this helps! have a lovely day <3

7 0

2 years ago