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zhenek [66]
3 years ago
8

Find the product of 395 ×76.estimate to check that the answer is reasonable

Mathematics
2 answers:
Orlov [11]3 years ago
6 0

Answer:

30020

estimate 395 x 75 = 29625

the answer is reasonable

Step-by-step explanation:

Reptile [31]3 years ago
3 0

Answer:

an estimation is 30000

Step-by-step explanation:

An estimate is a number that is close, so we round 395 to 400 and 76 to 75

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The sum of 42 and x is equal to 97.45. What's the equation for the sentence?!! Help!
gogolik [260]

Answer:

X = 97.45 - 42

Step-by-step explanation:

If 42 + X = 97.45, X needs to be 97.45 - 42

you can do the same thing with smaller numbers, for example:

5 + X = 7

7 - 5= 2 and you can check for sure that this is the answer by adding them together 5 + 2= 7 so it's definitely the right answer

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8 0
3 years ago
Check whether the relation R on the set S = {1, 2, 3} is an equivalent
kozerog [31]

Answer:

R isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let S denote a set of elements. S \times S would denote the set of all ordered pairs of elements of S\!.

For example, with S = \lbrace 1,\, 2,\, 3 \rbrace, (3,\, 2) and (2,\, 3) are both members of S \times S. However, (3,\, 2) \ne (2,\, 3) because the pairs are ordered.

A relation R on S\! is a subset of S \times S. For any two elementsa,\, b \in S, a \sim b if and only if the ordered pair (a,\, b) is in R\!.

 

A relation R on set S is an equivalence relation if it satisfies the following:

  • Reflexivity: for any a \in S, the relation R needs to ensure that a \sim a (that is: (a,\, a) \in R.)
  • Symmetry: for any a,\, b \in S, a \sim b if and only if b \sim a. In other words, either both (a,\, b) and (b,\, a) are in R, or neither is in R\!.
  • Transitivity: for any a,\, b,\, c \in S, if a \sim b and b \sim c, then a \sim c. In other words, if (a,\, b) and (b,\, c) are both in R, then (a,\, c) also needs to be in R\!.

The relation R (on S = \lbrace 1,\, 2,\, 3 \rbrace) in this question is indeed reflexive. (1,\, 1), (2,\, 2), and (3,\, 3) (one pair for each element of S) are all elements of R\!.

R isn't symmetric. (2,\, 3) \in R but (3,\, 2) \not \in R (the pairs in \! R are all ordered.) In other words, 3 isn't equivalent to 2 under R\! even though 2 \sim 3.

Neither is R transitive. (3,\, 1) \in R and (1,\, 2) \in R. However, (3,\, 2) \not \in R. In other words, under relation R\!, 3 \sim 1 and 1 \sim 2 does not imply 3 \sim 2.

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Three more than the quotient of a number and 4 is equal to 8
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3+ x/4=8


................

..
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