For these kinds of questions you should first solve for x:
y +36 = x^2 ⇒ √y+36 = x
now the inverse of this equation is:
√x + 36 = y :)))
i hope this is helpful
have a nice day
Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
<span>Part
A: Solve A = (x + 23) for x.
A = x + 23
=> A - 23 = x + 23 - 23
=> A - 23 = x
=> x = A - 23 <------- answer
Part B: Determine the value of x
when A = 108
Replace the value of A in the expression x = A - 23
x = 108 - 23 = 75
x = 75 <------- answer
Part C: Solve -np - 90 > 30 for n.
-np - 90 > 30
=> -np + np - 90 >30 + np
=> - 90 > 30 + np
=> -90 - 30 > 30 - 30 + np
=> -120 > np
=> np < - 120 <----- answer
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