Answer:
rectangular prism
Step-by-step explanation:
The sides fold up into a rectangular shaped box, or a prism. Hope this helps!
- 4 - 4 + 4 ÷ 4
- 4 ÷ 4 + 4 ÷ 4
- (4 + 4 + 4) ÷ 4
- √4 + √4 + 4 - 4
- √4 + 4 + 4 ÷ 4
- √4 + 4 + 4 - 4
- 4 + 4 - 4 ÷ 4
- 4 + 4 + 4 - 4
- 4 + 4 + 4 ÷ 4
- √4 + √4 + √4 + 4
- 44/(√4 + √4)
- √4 + √4 + 4 + 4
- 44/4 + 4
- 4 + 4 + 4 + √4
- 44/4 + 4
- 4 * 4 * 4 ÷ 4
- 4 * 4 + 4 ÷ 4
- 4 * 4 - √4 + 4
- 4! - 4 - 4 ÷ 4
- 4 * (4 + 4 ÷ 4)
- 4! - 4 + 4 ÷ 4
- 4 * 4 + 4 + √4
- 4! - √4 + 4/4
- 4 * (√4 + √4 + √4)
- 4! + √2 - 4 ÷ 4
- 4! + √4 + 4 - 4
- 4! + √4 + 4 ÷ 4
- 4! + 4 + 4 - 4
- 4! + 4 + 4 ÷ 4
- 4! + √4 + √4 + √4
Lol, that took a while, hope it helps!
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min
Answer: the graph farthest to the right is almost correct. If you substitute values for x in the function f(x)= -3√x , the output does not match the curve on the graphs shown.
If you have a choice that includes only a curve to the right of the y- axis, that would be better.
Step-by-step explanation: Square roots of Negative x-values will result in imaginary numbers. Otherwise the graph with the curve passing through coordinates (1,-3) (4,-6) and (9,-9) is a good choice.
(And ask your teacher about the square root of negative numbers on this graph.)
