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Tanzania [10]
3 years ago
10

according to the general equation for conditional probability of p(an B) = 3/10 and P(B)= 3/5, what is P(A|B)

Mathematics
2 answers:
qaws [65]3 years ago
4 0
The required formula is:
P(A | B)=\frac{P(A\cap B)}{P(B)}
Therefore the probability of A given B is:
P(A|B)=\frac{\frac{3}{10}}{\frac{3}{5}}=\frac{3\times5}{10\times3}=\frac{1}{2}
astraxan [27]3 years ago
4 0

Answer: its 1/2

Step-by-step explanation:

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Isabella wrote 0.0135<0.01350 because 135 <1350.Is Isabella correct?Why or Why not?
ElenaW [278]
She is wrong because <span>0.0135=0.01350</span>
8 0
3 years ago
Find the new amount given the original amount and the percent of change. $35,000; 7% decrease​
SpyIntel [72]

Answer:

7%=50

34950 7% decrease

35050 7% increase

Step-by-step explanation:

if 35000 is before the 7% decrease then it would be 34950

if after 35050

6 0
3 years ago
Find the minimum and maximum of f(x,y,z)=x^2+y^2+z^2 subject to two constraints, x+2y+z=4 and x-y=8.
Alika [10]
The Lagrangian for this function and the given constraints is

L(x,y,z,\lambda_1,\lambda_2)=x^2+y^2+z^2+\lambda_1(x+2y+z-4)+\lambda_2(x-y-8)

which has partial derivatives (set equal to 0) satisfying

\begin{cases}L_x=2x+\lambda_1+\lambda_2=0\\L_y=2y+2\lambda_1-\lambda_2=0\\L_z=2z+\lambda_1=0\\L_{\lambda_1}=x+2y+z-4=0\\L_{\lambda_2}=x-y-8=0\end{cases}

This is a fairly standard linear system. Solving yields Lagrange multipliers of \lambda_1=-\dfrac{32}{11} and \lambda_2=-\dfrac{104}{11}, and at the same time we find only one critical point at (x,y,z)=\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right).

Check the Hessian for f(x,y,z), given by

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite, since \mathbf v^\top\mathbf{Hv}>0 for any vector \mathbf v=\begin{bmatrix}x&y&z\end{bmatrix}^\top, which means f(x,y,z)=x^2+y^2+z^2 attains a minimum value of \dfrac{480}{11} at \left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right). There is no maximum over the given constraints.
7 0
3 years ago
Please help. due today.
guapka [62]

Answer:

1, 1/2, 1 1/2

Step-by-step explanation:

Question 1

20 divided by 18 is 1.1

So the answer is closest to 1

Question 2

9 divided by 20 is 0.45

So the answer is closest to 1/2

Question 3

7 divided by 5 is 1.4

So the answer is closest to 1 1/2

Hope this helps!

3 0
2 years ago
3a + 10 − 4q + 7a − 4q − 6.
soldi70 [24.7K]

Answer:

Step-by-step explanation:

3a+10-4q+7a-4q-6  combine terms

10a-8q+4

7 0
2 years ago
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