Length should be 2/5yd:
18inch*1yd/36inch=.5yd=> depth
volume= 2(length*width+lenght*depth+depth*width)
let l to be the length.
volume= 2(l*2+2(.5)+.5*2)
volume=5l+2
4=5l+2
2=5l
l=2/5
you multiply the number of years
Answer: The answer is 400 blue marbles.
Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.
So, number of red marbles is

and number of blue marbles is

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

Thus, 400 blue marbles need to be added to the bag.
Answer:
$5,300
Step-by-step explanation:
Formulae used,



Where,





Putting the values from the table, we get the best fit line as,

As we want to calculate the profit at 350 pounds, so putting x=350, we get
