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EastWind [94]
3 years ago
15

How can I solve this does anyone knows?

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0
A. C = 17h + 15
b. 83 = 17h + 15 
    -15           - 15  subtract 15 from both sides 
    68 = 17h
    ------------
         17               divide both sides by 17
      4=h  
  They cleaned the house for 4 hours
c. C = 20x
to do this last part, you would put both equations into the calculator under y=, then look at the table to determine when the price is the same. According to the calculator, the price is the same at 5 hours 
Ksju [112]3 years ago
4 0
I’m sorry but I don’t know number 3
1)15+17h
2)4 hours
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3 0
2 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
2 years ago
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