Answer:
2w + 2
Step-by-step explanation:
Width = w
Twice its width = 2*w =2w
2 inches more than twice its width = 2w + 2
Length = 2w + 2
Your answer is either A or D
Answer:
y = 2/3x - 3
Step-by-step explanation:
Step 1: Write equation
2x - 3y = 9
Step 2: Solve for <em>y</em>
- Subtract 2x on both sides: -3y = 9 - 2x
- Divide both sides by -3: y = -3 + 2/3x
- Rewrite: y = 2/3x - 3
Answer:



The standard deviation will remain unchanged.
Step-by-step explanation:
Given

Solving (a): The range
This is calculated as:

Where:

So:


Solving (b): The variance
First, we calculate the mean




The variance is calculated as:

So, we have:
![\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B6-1%7D%2A%5B%28136%20-%20135%29%5E2%20%2B%28129%20-%20135%29%5E2%20%2B%28141%20-%20135%29%5E2%20%2B%28139%20-%20135%29%5E2%20%2B%28138%20-%20135%29%5E2%20%2B%28127%20-%20135%29%5E2%5D)
![\sigma^2 =\frac{1}{5}*[162]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B5%7D%2A%5B162%5D)

Solving (c): The standard deviation
This is calculated as:


--- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.
Answer:
Because the line is the shortest path between 2 points