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Ira Lisetskai [31]
3 years ago
14

If you have 6.02x10^23 molecules of trisulfur monoxide, how many grams would it weigh?

Chemistry
1 answer:
Cloud [144]3 years ago
3 0

Answer:

112.18 g.

Explanation:

you're using stoichiometry to find the mass of the compound S₃O.

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How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?
jolli1 [7]

Answer:

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

where R is the molar constant of the gases and n the number of moles.

In this case you know:

  • P= 7.5 atm
  • V= 2.3 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 24 °C= 297 °K (being 0°C=273°K)

Replacing:

7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K

Solving:

n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}

n=0.708 moles

Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

mass=\frac{0.708 moles*32 grams}{1mole}

mass= 22.656 grams

<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>

8 0
3 years ago
Read 2 more answers
Which is the best explanation of why heat is released when
vazorg [7]
The answers is A. Reales energy stored in chemical bonds
6 0
3 years ago
What is the radioactive nucleus before it decays​
Darina [25.2K]

Answer:

Alpha decay is one type of radioactive decay, in which an atomic nucleus emits an alpha particle, and thereby transforms (or "decays") into an atom with a mass number decreased by 4 and atomic number decreased by 2.

Explanation:

7 0
3 years ago
The rate law for the reaction 2A + B →C is –rA= kACA2CBwithkA= 25 (L/mol)2sec. What arekBandkC?
givi [52]

Explanation:

The given reaction equation is as follows.

             2A + B \rightarrow C

So, rate constants for different reactants and products written as follows.

             \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

         A = -2

         B = -1

         C = 1

Therefore,

      \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

      \frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}    

             \frac{-k_{A}}{-2} = k_{B} = k_{C}

Hence,          k_{B} = k_{C} = \frac{25}{2} (L/mol)^{2}

                                          = 12.5 (L/mol)^{2}

Thus, we can conclude that k_{B} and k_{C} are 12.5 (L/mol)^{2}.

5 0
3 years ago
What is the concentration of h+ ions in a solution of hydrochloric acid that was prepared by diluting 15.0 ml of concentrated (1
il63 [147K]
HCl is a monoprotic acid, which means that each mole of HCl releases one mole of hydrogen ions upon dissociation. Therefore, we calculate the moles of HCl present using:

Moles = Molarity * Volume (in liters)

Moles = 11.6 * 0.015
Moles = 0.174 moles of HCl = moles of H+ ions

Now, we use the same formula to calculate the molarity of the new solution, since the number of moles remains constant.

0.174 = M * 0.5
M = 0.348 M

The molarity of the new solution is 0.348
7 0
3 years ago
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