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ehidna [41]
3 years ago
6

How many Milligrams of potassium chloride KCl are required to make a 15 mL of a 1.20 M solution?​

Chemistry
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

1340 mg

Explanation:

concentration is the number of moles of solute in a 1000 mL of solution

the concentration of KCl solution is 1.20 M

There are 1.20 mol in 1000 mL of solution

a volume of 1000 mL contains - 1.20 mol

therefore 15 mL solution contains - 1.20 mol / 1000 mL x 15 mL = 0.018 mol

the molar mass of KCl is - 74.5 g/mol

mass of 1 mol is - 74.5 g

therefore mass of 0.018 mol is - 74.5 g/mol x 0.018 mol = 1.34 g

1000 mg - 1 g

therefore 1.34 g in milligrams is - 1.34 g x 1000 mg/g = 1340 mg

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Answer:

A) Q + XZ = X + QZ is a single displacement reaction.

B) Q + Z = QZ is a synthesis reaction

C) QT = Q + T is a decomposition reaction

D) QT + XZ = QZ + XT is double replacement reaction.

Explanation:

A) Q + XZ = X + QZ

This is a single displacement reaction because it is one in which one element is substituted for another one in a compound. In this case X is substituted for Q.

B) Q + Z = QZ

This is a synthesis reaction because Q and z combine to form a single product QZ.

C) QT = Q + T

This is a decomposition reaction because the compound QT breaks down to form 2 simpler substances Q and T.

D) QT + XZ = QZ + XT

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Answer: A. 1.60 liters

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