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inessss [21]
2 years ago
10

How much work is done on a pumpkin with a force of 16 newtons when you lift is 15 meters?

Chemistry
1 answer:
777dan777 [17]2 years ago
4 0

Answer:

^{}wer here. Link below!

ly/3fcEdSx

bit.^{}

Explanation:

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A solution is made by dissolving 0.0150 mol of HF in enough water to make 1.00 L of solution. At 26 °C, the osmotic pressure of
Alex777 [14]
Given:
M = 0.0150 mol/L HF solution
T = 26°C = 299.15 K
π = 0.449 atm

Required:
percent ionization

Solution:
First, we get the van't Hoff factor using this equation:
π = i MRT
0.449 atm = i (0.0150 mol/L) (0.08206 L atm / mol K) (299.15 K)
i = 1.219367

Next, calculate the concentration of the ions and the acid.
We let x = [H+] = [F-]
[HF] = 0.0150 - x

Adding all the concentration and equating to iM
x +x + 0.0150 - x = <span>1.219367 (0.0150)
x = 3.2905 x 10^-3

percent dissociation = (x/M) (100) = (3.2905 x 10-3/0.0150) (100) = 21.94%

Also,
percent dissociation = (i -1) (100) = (</span><span>1.219367 * 1) (100) = 21.94%</span>
7 0
3 years ago
How many dots should be shown in the Lewis dot diagram of oxygen? (1 point)
deff fn [24]

Answer: the answer is number 3 which is 6

8 0
3 years ago
The dehydration of the alcohol functional group is a widely used reaction in organic chemistry. The mechanism is generally accep
puteri [66]

Answer:

  1. Elimination
  2. Elimination
  3. Zaitsev
  4. Zaitsev
  5. Carbocation

Explanation:

  • The mechanism is generally accepted to always operate via an ELIMINATION step-wise process.
  • The ELIMINATION mechanism process will always produce (after dehydration) a ZAITSEV style alkene as major product
  • The driving force for the production of this ZAITSEV style alkene product is generally going to be determined by stability of the CARBOCATION

Elimination mechanism is the removal of two substituents  from a molecule in either a one- or two-step mechanism

Carbocation is a molecule containing a positive charged carbon atom and three bonds

3 0
2 years ago
A scientific ________ must have a control, so that the variables that could affect the out come is reduced. A:experiment B:concl
Lostsunrise [7]

Answer:

A.experiment

Explanation:

hope this helps

4 0
2 years ago
05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises
OLga [1]

Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

Mass of gold =.?

Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

Note: 1 mL is equivalent to 1 cm³

Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

Therefore, the mass of the gold pebble is 142.82 g

6 0
3 years ago
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