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3 years ago

One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer ?

1 answer:

4 0

Answer first number = 57 second number = 41
x= 16 + y
x + 2y = 139

16+ y + 2y =139
16 + 3y =139
16-16 +3y = 139-16
3y = 123
3/3y = 123/3
y= 41

x= 16+y
x = 16+41
x= 57

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Answer:

The slope of a line that includes the points (4, -2) and (5, 0) is 2

Step-by-step explanation:

You know that the formula y - y1 = m(x - x1) is the point-slope form of the equation of a line where m is the slope of a line.

The line must include the points (4, -2) and (5, 0). So, being:

(x,y)= (4,-2)
(x1,y1)= (5, 0)

and replacing in the point-slope form of the equation of a line:

-2-0=m(4-5)

You solve the equation for m and get:

-2=m*(-1)

$m=\frac{-2}{-1}$

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3 years ago

One of the tables shows a proportional relationship. Graph the line representing the proportional relationship from this table i

Mkey [24]

Answer:

Table C

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Find the value of the constant of proportionality in each table

Table A

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-3$ ------> $k=-3/-1=3$

This table has different values of k

therefore

the table A does not represent a proportional relationship

Table B

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=3$ ------> $k=3/1=3$

This table has different values of k

therefore

the table B does not represent a proportional relationship

Table C

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=4$ ------> $k=4/2=2$

This table has the same value of k

therefore

the table C represent a proportional relationship

Table D

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=6$ ------> $k=6/2=3$

This table has different values of k

therefore

the table D does not represent a proportional relationship

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Answer:

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Step-by-step explanation:

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