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3 years ago

One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer ?

1 answer:

4 0

Answer first number = 57 second number = 41
x= 16 + y
x + 2y = 139

16+ y + 2y =139
16 + 3y =139
16-16 +3y = 139-16
3y = 123
3/3y = 123/3
y= 41

x= 16+y
x = 16+41
x= 57

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3 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints

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Answer:

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Step-by-step explanation:

I will be writing the equation of the perpendicular bisector in the slope-intercept form which is y=mx +c, where m is the gradient and c is the y-intercept.

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3 years ago

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3 years ago

Read 2 more answers

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