One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer ?
1 answer:
Answer first number = 57 second number = 41
x= 16 + y
x + 2y = 139
16+ y + 2y =139
16 + 3y =139
16-16 +3y = 139-16
3y = 123
3/3y = 123/3
y= 41
x= 16+y
x = 16+41
x= 57
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