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Drupady [299]
3 years ago
13

What is bigger 4/5 or 8/10

Mathematics
2 answers:
statuscvo [17]3 years ago
6 0
They are equal because if you make 4/5 into a denominator of 10 it is 8/10
Pachacha [2.7K]3 years ago
4 0
4/5 equals 8/10 so non of them are bigger than each other.
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Simplify.<br><br><br><br> If d = –3, evaluate –d.<br><br><br><br> –3<br><br> 1<br><br> 0<br><br> 3
AnnZ [28]
-d would equal 3. just flip its around right?
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Anuta_ua [19.1K]

Answer:yes

Step-by-step explanation:

There is one very important exception to the rule that multiplying or dividing an inequality is the same as multiplying or dividing an equation. Whenever you multiply or divide an inequality by a negative number, you must flip the inequality sign.

6 0
3 years ago
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Evaluate the expression. ​ (26÷13)⋅(−7)+14−4 ​
Bas_tet [7]
Follow pemdas. Evaluate operations in parentheses first.
2*(-7)+14-4

Then multiply
-14+14-4

Then add and subtract from left to right
-14+14=0
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Final answer: -4
6 0
4 years ago
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Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q2+11q
Sedbober [7]

Answer:

(q+\frac{11}{2})^2-\frac{121}{4}

Step-by-step explanation:

We have been given an expression q^2+11q. We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form a^2+2ab+b^2.

To convert our given expression into perfect square trinomial, we need to add and subtract (\frac{b}{2})^2 from our given expression.

We can see that value of b is 11, so we need to add and subtract (\frac{11}{2})^2 to our expression as:

q^2+11q+(\frac{11}{2})^2-(\frac{11}{2})^2

Upon comparing our expression with (a+b)^2=a^2+2ab+b^2, we can see that a=q, 2ab=11q and b=\frac{11}{2}.

Upon simplifying our expression, we will get:

(q+\frac{11}{2})^2-\frac{11^2}{2^2}

(q+\frac{11}{2})^2-\frac{121}{4}

Therefore, our perfect square would be (q+\frac{11}{2})^2-\frac{121}{4}.

8 0
3 years ago
Read 2 more answers
( x + 2 )^2 - ( y + 2 )^2
GarryVolchara [31]

The difference of two squares factoring pattern states that a difference of two squares can be factored as follows:

a^2-b^2 = (a+b)(a-b)

So, whenever you recognize the two terms of a subtraction to be two squares, you can factor it as the sum of the roots multiplied by the difference of the roots.

In this case, the squares are obvious: (x+2)^2 is the square of x+2, and (y+2)^2 is the square of y+2

So, we can factor the expression as

(x+2)^2 - (y+2)^2 = [(x+2)+(y+2)] - [(x+2)+(y+2)]

(the round parenthesis aren't necessary, I used them only to make clear the two terms)

We can simplify the expression summing like terms:

(x+2)^2 - (y+2)^2 = [(x+2)+(y+2)][(x+2)-(y+2)] = (x+y+4)(x-y)

3 0
3 years ago
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