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2 years ago

Find an order pair (x,y) that is solution to the equation 3x-y=8

Mathematics

2 answers:

Ivahew [28]2 years ago

7 0

Answer:

(2.67,-8)

Step-by-step explanation:

You first make x 0 so it is -3x0 to cancel that out to find y. You then see that you get -y=8 so you make y positive by moving the negative to the other side to get y = -8. Then, you do the same type of process for x and get 2.67. I could be wrong but wanted help as much as I could!

bogdanovich [222]2 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

If z1 = 12(cos55° + isin55°) and z2 = 4(cos95° + isin95°), then |z1z2|= ???

zaharov [31]

$\bf \begin{cases}
z_1=12[cos(55^o)+i~sin(55^o)]\\\\
z_2=4[cos(95^o)+i~sin(95^o)]
\end{cases}\\\\
-------------------------------$

$\bf ~~~~~~\textit{ product of two complex numbers}\\\\
{{ r_1}}[cos({{ \alpha}})+isin({{ \alpha}})]\quad \cdot \quad {{ r_2}}[cos({{ \beta}})+isin({{ \beta}})]
\\\\\\
\implies {{ r_1\cdot r_2}}[cos({{ \alpha}} + {{ \beta}})+isin({{ \alpha}} + {{ \beta}})]\\\\
-------------------------------\\\\
z_1\cdot z_2\implies 12\cdot 4[cos(55^o+95^o)+i~sin(55^o+95^o)]
\\\\\\
48[cos(150^o)+i~sin(150^o)]
\\\\\\
|~48[cos(150^o)+i~sin(150^o)]~|\implies 48[cos(150^o)+i~sin(150^o)]$

6 0

3 years ago

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.

Tanya [424]

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

<h3>What is mean, median and mode of a data set?</h3>

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

The mean is-

$\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5$

The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41 41 43 43 45 50 52 53 54 62 63 63 67 75 97

The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

$r=97-41\\r=56$

The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

$IQR=63-23\\IQR=20$

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

brainly.com/question/14532771

#SPJ1

4 0

1 year ago

Is 7/45 a repeating or terminating

timurjin [86]

I believe that 7/45 is a repeating decimal

8 0

3 years ago

If you have a chance to win $500 for drawing a card of 10 of any suit from a standard deck of cards, what is the value of expect

Dimas [21]

The expected value is $38.46.

The probability of drawing a 10 from any suit is 4/52. Multiply this by the earnings, 500:

4/52(500) = 2000/52 = 38.46

6 0

3 years ago

Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest

Ludmilka [50]

Answer:

$6 \times 10^{7}$

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = $10^{7}$

Since, there are 6 toll-free are codes in total, the total number of toll-free numbers for all 6 area codes = $6 \times 10^{7}$

4 0

3 years ago