Answer:
Explanation:
Magnitude of force per unit length of wire on each of wires
= μ₀ x 2 i₁ x i₂ / 4π r where i₁ and i₂ are current in the two wires , r is distance between the two and μ₀ is permeability .
Putting the values ,
force per unit length = 10⁻⁷ x 2 x i x 2i / ( 6 x 10⁻³ )
= .67 i² x 10⁻⁴
force on 3 m length
= 3 x .67 x 10⁻⁴ i²
Given ,
8 x 10⁻⁶ = 3 x .67 x 10⁻⁴ i²
i² = 3.98 x 10⁻²
i = 1.995 x 10⁻¹
= .1995
= 0.2 A approx .
2 i = .4 A Ans .
Answer:
A) the space inbetween the waves
B) frequency
C) the frequency gets higher
Explanation:
Odd though it seems at first, gravity is pulling the cat down while the floor is pushing the cat up - in equal amounts. Forces are absolutely acting on the cat but they balance - so there is no net force.
Answer:
- 93.6 N in the 41° cable
- 155.6 N in the 63° cable
- 200 N in the vertical cable
Explanation:
Let T and U represent the tensions in the 41° and 63° cables, respectively. In order for the system to be stationary, the horizontal components of these tensions must balance, and the vertical components of these tensions must total 200 N.
Tcos(41°) =Ucos(63°) . . . . . balance of horizontal components
U = Tcos(41°)/cos(63°) . . . . write an expression for U
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The vertical components must total 200 N, so we have ....
Tsin(41°) +Usin(63°) = 200
Tsin(41°) +Tcos(41°)sin(63°)/cos(63°) = 200
T(sin(41°)cos(63°) +cos(41°)sin(63°))/cos(63°) = 200
T = 200cos(63°)/sin(41° +63°) ≈ 93.6 . . . newtons
U = 200cos(41°)/sin(41° +63°) ≈ 155.6 . . . newtons
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The vertical cable must have sufficient tension to balance the weight of the traffic light, so its tension is 200 N.
Then the tensions in the 3 cables are ...
41°: 93.6 N
63°: 155.6 N
90°: 200 N
