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4 years ago

Which statements are true the ordered pair (1, 2) and the system of equations?

1 answer:

3 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the answers:
<span>When (1, 2) is substituted into the first equation, the equation is false.
</span><span>
The ordered pair (1, 2) is not a solution to the system of linear equations.

The ordered pair (1, 2) is a solution to the system of linear equations.</span>

You might be interested in

What is the value of x? x−15=8 in simplest form.

yanalaym [24]

Answer:

x = 23

Step-by-step explanation:

Isolate x.

x - 15 = 8

x = 15 + 8

x = 23

4 0

3 years ago

Read 2 more answers

Please Help!!! Determine the intercepts of the line that corresponds to the following table of values.

Orlov [11]

Answer:

y-intercept is (0,30); x-intercept is (52.5,0).

Step-by-step explanation:

Note that as x increases by 7 from -35 to -28, y decreases by 4 from 18 to 14. Thus, the slope of this line is

m = rise / run = -4/7.

Let's find the equation of the line. Start with the slope-intercept form:

y = mx + b. Use the slope m = -4/7 and the point (-28, 14) to find b:

14 = -(4/7)(28) + b, or

14 = -16 + b. Then b = 30, and the equation of the line in slope-intercept form is y = (-4/7)x + 30. The y-intercept is (0, 30).

Find the x-intercept by setting y=0 and solving the resulting equation for x:

y = (-4/7)x + 30 becomes (4/7)x = 30, and x = (7/4)(30) = 214, or 52.5.

The x-intercept is thus (52.5, 0).

6 0

3 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

I have a pet golden retriever. Each year it gains 11.4 pounds. He is 8 1\2 years old how many pounds does he weigh?

grigory [225]

I think he weighs 461.7 but I would check that

4 0

3 years ago

Please help i'll give brainliest

Aliun [14]

Answer:

-01/0/0.8/1.2/1.6

Step-by-step explanation:

3 0

3 years ago