We use the given masses of the reactants to calculate the moles of Mn and Cl. Empirical formula represents the simplest mole ratio of atoms present in a compound.
Moles of Mn = ![12.99 g Mn * \frac{1 mol Mn}{54.94 g Mn} = 0.236 mol Mn](https://tex.z-dn.net/?f=%2012.99%20g%20Mn%20%2A%20%5Cfrac%7B1%20mol%20Mn%7D%7B54.94%20g%20Mn%7D%20%3D%200.236%20mol%20Mn%20)
Moles of Cl =
= 0.710 mol Cl
Simplest mole ratio: ![Mn_{\frac{0.236}{0.236}}Cl_{\frac{0.710}{0.236}}](https://tex.z-dn.net/?f=%20Mn_%7B%5Cfrac%7B0.236%7D%7B0.236%7D%7DCl_%7B%5Cfrac%7B0.710%7D%7B0.236%7D%7D%20%20%20%20%20)
So the empirical formula is ![MnCl_{3}](https://tex.z-dn.net/?f=%20MnCl_%7B3%7D%20%20)
The answer is D:store
It is hard to store thermal energy because it just dissipates rapidly.
Everywhere
Hope that helps and good luck
~May
Answer:
potential energy into heat and kinetic energy.
Explanation:
Answer:
0.3936 J/gC
Explanation:
using the formula: q=mcΔt
q= 7032J
m=812g
ΔT = 22C
plug in and solve:
7032=(812)(c)(22)
c=7032/(812)(22)
c=0.39 J/gC