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Tatiana [17]
3 years ago
10

What are similarities between opinion based research and observation based research

Chemistry
1 answer:
Harman [31]3 years ago
8 0
I dont know try looking it up on google
You might be interested in
Which of the following BEST describes temperature? *
Archy [21]

Answer:

the average kinetic energy of a system

Explanation:

the more kinetic energy in something, the hotter it is, the less kinetic energy in something, the cooler it is. gases have the most kinetic energy. solids have the least, but everything has kinetic energy

7 0
3 years ago
An unknown element has two isotopes: one whose mass is 68.926 amu (60.00% abundance) and the other whose mass is 70.925 amu (40.
scZoUnD [109]

Answer:

69.726 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 68.926 amu

Abundance of A (A%) = 60.00%

Isotope B:

Mass of B = 70.925 amu

Abundance of B (B%) = 40.00%

Average atomic mass =?

The average atomic mass of the element can be obtained as shown below:

Average atomic mass

= [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

= [(68.926 × 60)/100] + [(70.925 × 40)/100]

= 41.3556 + 28.37

= 69.726 amu

Therefore, the average atomic mass of the element is 69.726 amu

7 0
3 years ago
Wavelengths are often represented in nm. What is the diameter of a helium (He) atom in
lianna [129]

Answer:

Diameter He = 0,1 nm.

Explanation:

Km to nm:

⇒ Diameter He = 1.0 E-13 Km * ( 1000 m / Km ) * (  1 E9 nm / m )

⇒ Diameter He = 0.1 nm

5 0
3 years ago
Read 2 more answers
The Henderson-Hasselbalch equation relates the pH of a buffer solution to the pKa of its conjugate acid and the ratio of the con
Kobotan [32]

Answer:

The correct answer is 190.5 mL of 1.00 M KH₂PO₄

Explanation:

A phosphate buffer is composed by phosphate acid (KH₂PO₄) and its conjugated base (K₂HPO₄). To obtain the relation between the concentrations of base and acid to add, we use Henderson-Hasselbach equation:

pH= pKa + log \frac{base}{acid}

We have: pH= 6.97 and pKa= 7.21. So, we replace the values in the equation:

6.97= 7.21 + log \frac{base}{acid}

6.97-7.21= log \frac{base}{acid}

-0.24= log \frac{base}{acid}

10^{-0.24}= \frac{base}{acid}

0.575 = \frac{base}{acid}

\frac{0.575}{1}= \frac{base}{acid}

It means that you have to mix a volume 0.575 times of conjugated base and 1 volume of acid. If we assume a total buffer concentration of 1 M, we have:

base + acid = 1

base= 1 - acid

We replace in the previous equation:

0.575= \frac{1-acid}{acid}

0.575 acid= 1 - acid

0.575 acid + 1 acid= 1

1.575 acid = 1

acid= 1/1,575

acid= 0.635

base= 1 - acid = 1 - 0.635 = 0.365

For a total volume of 300 ml, the volumes of both acid and base will be:

300 ml x 0.635 M = 190.5 ml of acid (KH₂PO₄)

300 ml x 0.365 M= 109.5 ml of base (K₂HPO₄)

We can corroborate our calculations as follows:

190.5 ml + 109.5 ml = 300 ml

109.5 ml / 190.5 ml = 0.575

4 0
3 years ago
What is the wavelength of 1.2*1015hz​
EleoNora [17]

Answer:

Explanation:

Hdhdh

6 0
3 years ago
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