Answer:
Explanation:
a) the units of the constants 200 and 10 are as follows:
unit of 200 = unit of r / unit of D
= crystals/min× mm
= crystals / (min×mm)
unit of 10 = unit of r / unit of D^2
= crystals/min × mm²
= crystals / (min×mm²)
b) The objective here is to determine the crystal nucleation rate in crystals/s corresponding to a crystal diameter of 0.050 inch; T o do that ; let's first convert the inch to mm
We all know that
1 inch = 25.4 mm
0.050 inch = 0.050 ×25.4 mm
= 1.27 mm
nucleation rate = 200×D - 10×D²
= 200×1.27 - 10×(1.27)²
=237.9 Crystals/min
=237.9/60 crystals/sec
= 3.96 crystals/sec
c) Derive a formula for r(crystals/s) in terms of D(inches). (See Example 2.6-1.) Check the formula using the result of Part b.
r(crystals/sec)=A D−B D²
(D in inch)
unit of 200= crystals / (min×mm)
unit of 10=crystals / (min×mm²
)
A = 200 crystals / (min×mm) × 1/60 min/sec ×25.4 mm/inch
= 84.7 crystals/(sec-inch)
B = 10 crystals / (min×mm²
) × 1/60 min/sec ×25.4 mm/inch×25.4 mm/inch
=107.5 crystals/(sec-inch)
Mass of iron sulfide obtained : 22 g
<h3>Further explanation</h3>
Reaction
<em>Fe+S⇒FeS</em>
8 grams of sulfur and 28 grams of iron are taken for the reaction
mol of Fe(Ar=56 g/mol) :
mol of S(Ar=32 g/mol) :
Limiting reactant ⇒ S(smaller mol ratio), excess reactant : Fe
mol of FeS based on limiting (S) ⇒0.25(mol ratio from equation = 1 : 1)
Mass FeS(MW=88 g/mol) :
C is the correct answer.<span>
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