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UNO [17]
3 years ago
11

When making an observation you should provide a general description of the subject rather than going into too much detail true o

r false
Chemistry
1 answer:
vodka [1.7K]3 years ago
8 0
In an observation in an experiment, you want to write down as much detail as possible. So the answer would be false.
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The two algae seen here are classified as green algae. That means they make their own food by photosynthesis. The algae on the l
ohaa [14]

Answer:

C

Explanation:

Unicellular algae can't do photosynthesis because it is a single cell organisms, therefore the answer is C

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3 years ago
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How many Valence Electrons do Lithium has ??
faltersainse [42]

Answer:

one valence electron

Lithium has a single electron in the second principal energy level and so we say that lithium has one valence electron. Beryllium has two valence electrons.

- Lumen Learning

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3 years ago
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PLS HELP QUICKLY I WILL GIVE 79 POINTS FOR YALL TO ANSWER THIS QUESTION!
Daniel [21]

Answer:

Magnesium and strontium

Explanation:

11 protons and 11 electrons, 12 neutrons.

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4 0
4 years ago
Select the fraction that is equivalent to 1/2
zhannawk [14.2K]

Answer:

5/10,

10/20,

3/6

4/8

6/12

3 0
3 years ago
Compounds A and BB are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 gg of su
Lelechka [254]

Answer:

Mass ratio of sulfur and oxygen in compounds A and B is 3:2 which confirms that the mass ratios in the two compounds are simple multiples of each other

Explanation:

This question seeks to establish/confirm the law of multiple proportions which  posits that elements combine to form different substances which are whole number multiples of each other. Best example of this plays out in the formation of several oxides of the same element. Looking at the ratio in which the elements combine in each of the oxides, we can assume that these ratios are simple whole number multiples of each other.

Now back to the question.

In substance A, we have 6 g of sulfur combining with 5.99 g of oxygen

Now, lest us calculate the ratio of the mass of sulfur to that of oxygen = 6g/5.99g = 1

Now let us calculate the mass ratio of sulfur to oxygen in the second compound = 8.6/12.88 = 0.668

Now the ratios in both compounds are 1 to 0.668. 0.668 to fraction is approximately 1/1.5.

So therefore, the ratio we are having would be 1:1/1.5 or 1:0.668

This is same as 1/(1÷1.5) which is 1.5/1 or simply 3/2

This gives a ratio of approximately 1.5 to 1 or 3 to 2

The ratio 3 to 2 indicates that the mass ratios in both com pounds are simple multiples of each other

5 0
4 years ago
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