Answer:
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Step-by-step explanation:
Bill's answer is wrong because timesing 150 by 1.3 is increasing the number by 30%, not 3%
If he wanted to use this method, he would have ti times 150 by 1.03
Answer:
option (a) $6,240
Step-by-step explanation:
Given:
Purchasing cost of the equipment = $82,000
Estimated life = 5 years
Salvage value = $4,000
Revised expected life = 8 years
Now,
Depreciation per year =
therefore,
The accumulated Depreciation at the beginning of year 4
= Annual depreciation × years passed
= 15,600 × 3
= $46,800
Thus,
The book value at the beginning of year 4
= Purchasing cost - Depreciation
= $82,000 - $46,800
= $35,200
Now,
The remaining life = Revised estimated life - Years passed
= 8 - 3
= 5 years
therefore,
Depreciation expense =
=
= $6,240
Hence,
The correct answer is option (a) $6,240
Okay. So when you solve 864/31 on a sheet of paper and you divide it properly, the remainder you get should be 27. The answer is B: 27.
24q-8=11 (use distributive property)
24q= 11+8
24q = 20
q= 20/24
q= 0.8
Answer:
Step-by-step explanation:
Let x represent the total number of stdents that has all grades in the school.
There are three grades in the school. One grade has 1/3 of the students, this means that number of students that belongs tho this grade is 1/3 × x = x/3
One grade has 1/4 of the students, this means that number of students that belongs to this grade is 1/4 × x = x/4
Total number of students in both grades would be x/3 +/x/4 = 7x/12
The number of students in the remaining grade would be
x - 7x/12 = 5x/12
fraction of students in the remaining grade would be
(5x/12)/x = 5/12