Answer:
35 °C is the final temperature.
Comment if you need step to step explanation.
Answer:
The volume is increased.
Explanation:
According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;
V₁ / T₁ = V₂ / T₂ -----(1)
In statement the data given is,
T₁ = 10 °C = 283.15 K ∴ K = 273.15 + °C
T₂ = 20 °C = 293.15 K
So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,
V₁ = 100 L
V₂ = Unknown
Now, we will arrange equation 1 for V₂ as,
V₂ = V₁ × T₂ / T₁
Putting values,
V₂ = 100 L × 293.15 K / 283.15 K
V₂ = 103.52 L
Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.
Answer:
The short of it is you would create salt.
Explanation:
If sodium metal and chlorine gas mix under the right conditions, they will form salt. The sodium loses an electron, and the chlorine gains that electron. This reaction is highly favorable because of the electrostatic attraction between the particles. In the process, a great amount of light and heat is released.
Answer:
2.8M
Explanation:
The following data were obtained from the question:
Volume of stock solution (V1) = 40mL
Molarity of the stock solution (M1) = 7M
Volume of diluted solution (V2) = 100mL
Molarity of diluted solution (M2) =?
Using the dilution formula, we can easily find the molarity of the diluted solution as follow:
M1V1 = M2V2
7 x 40 = M2 x 100
Divide both side by 100
M2 = (7 x 40)/100
M2 = 2.8M
Therefore, the molarity of the diluted solution is 2.8M
Answer:
Al(OH)- 4,
Explanation:
NaOH added to 0.010 M Al3+
The predominant species at equilibrium will be = Al(OH)- 4, and this because sodium hydroxide ( NaOH ) is a base will readily form a stable complex ion with aluminum ion like ( Al( OH ) - 4 . also the higher the Kf value the more stable the complex ion becomes and the more soluble Al(OH)3 becomes
hence the predominant species at equilibrium is : Al(OH)- 4,
