How does the law of conservation of matter apply to chemical equations?
1 answer:
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Answer:
The empirical formula of the compound is .
Explanation:
We need to determine the empirical formula in its simplest form, where hydrogen () is scaled up to a mole, since it has the molar mass, and both carbon (
) and oxygen (
) are also scaled up in the same magnitude. The empirical formula is of the form:
Where ,
are the number of moles of the carbon and oxygen, respectively.
The scale factor (), no unit, is calculated by the following formula:
(1)
Where:
- Mass of hydrogen, in grams.
- Molar mass of hydrogen, in grams per mole.
If we know that and
, then the scale factor is:
The molar masses of carbon () and oxygen (
) are
and
, then, the respective numbers of moles are: (
,
,
)
Carbon
(2)
Oxygen
(3)
Hence, the empirical formula of the compound is .
Answer:
The possible structures are shown in figure.
Explanation:
The seven isomers that could be formed from the given compound due to radical halogenation are shown in the figure.
We have mentioned only chlorine as group for showing just the chiral nature of the compound.
A chiral compound has a carbon with all the four groups different from each other.
There are three structures which are chiral (as shown).
W is the brominated product
X is the chlorinated product.
1) W reacts readily in water to form a chiral substitution product Y, C8H17OH.
Reaction of a single enantiomer of W produces a single enantiomer of Y as the only substitution product.: It means that the substitution is SN2 which is possible if the compund is not tertiary.
2) X likewise reacts readily in water though at a slower rate than W; a chiral substitution product Z, C8H17OH, is again formed. Unlike W, however, reaction of a single enantiomer of X produces Z that is nearly racemic.
It means that it will undergo SN1 reaction,. So the alkyl halide must be tertiary.
The possible structures are shown in figure.
