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ivanzaharov [21]
3 years ago
14

Answer the following questions using the results of the following Unknown Solution Analysis:

Chemistry
1 answer:
STALIN [3.7K]3 years ago
6 0

Answer:

(a). strontium iodide.

(b). SrI2.

Explanation:

This question wants to test our knowledge on qualitative part of chemistry practical.

The first part is flame test which is a physical test. The flame test that was done on the com gave red flame.

Deduction: This confirms the presence of Strontium and Calcium.

The next thing is the chemical tests.

(1). Unknown + ammonium carbonate: gives white precipitate (ppt.).

Deduction: presence of Calcium and Strontium ions

(2). Unknown + Ammonium phosphate - white ppt.

Deduction: presence of Calcium and Strontium ions.

(3). Unknown sample + ammonium sulfate - white ppt.

Deduction: presence of Strontium ion confirmed.

(3). Halide test: purple hexane layer.

Deduction: shows the presence of Iodine.

Therefore, the final conclusion can be made as;

(a). The name of the chemical compound is strontium iodide.

(b). The chemical formula for the compound is SrI2.

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What process forms an image in a mirror? Choices: A. absorbing light B. Reflecting light C. Refracting light D. Transmitting lig
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Answer

Using the law of reflection—the angle of reflection equals the angle of incidence—we can see that the image and object are the same distance from the mirror. This is a virtual image, since it cannot be projected—the rays only appear to originate from a common point behind the mirror.

Explanation:

Hope this helps someone

4 0
2 years ago
Which is a way you would expect two animals of the same species to differ?
LuckyWell [14K]
C is the correct answer
5 0
3 years ago
Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)
Stels [109]
<span>                                                    Au</span>₂(SeO₄)₃

                                         O = -2 × 4 = -8
                                             Se  =  + 6
So,
                                            (+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3
                                             
                                             -2 ₓ 3 = -6
Means,
                             Au₂ + (-6) = 0
               
                            Au₂  = +6
Or,
                            Au  =  6 / 2

                            Au  = +3
Result:
                            Au  =  +3
                            Se  =  +6
                            O   =  -2

                                                      Ni(CN)₂


Cyanide (CN⁻) contains -1 charge,
So,
                              N  =  -3
                              C  =  +2
Then,
                                         Ni + (-1)₂  =  0

                                               Ni - 2  =  0
Or,
                                                     Ni =  +2
Result:
                            N  =  -3
                            C  =  +2
                           Ni  =  +2




6 0
4 years ago
Anions are formed when *
soldier1979 [14.2K]
Anions are negative ions so it’s when an atom gains electrons
6 0
3 years ago
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