I need help with this one

VashaNatasha [74]

Hope this helps
Answer…

5 0

2 years ago

To prepare for virtual learning the school is purchasing extra keyboards, mice, and PC cameras. They have a budget of $1500 to s

leonid [27]

Answer:

20 keyboards and mice, 10 cameras.

Step-by-step explanation: They need the same number of keyboard and mice, and they want to get half the amount of cameras they do keyboard and mice. They have a budget of $1500 so 20 keyboards and mice as well as 10 cameras is the most optimal purchase.

30*20=600

20*20=400

50*10=500

600+400+500=1500

7 0

3 years ago

Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of

bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

= $\frac{7}{100}$

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = $1-\frac{7}{100}$

⇒ prob = $\frac{93}{100}$

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = $(\frac{93}{100})^{12}$