F(x) = x² + 4x - 12

x = -b/2a
x = -(4)/2(1)
x = -4/2
x = 2

f(x) = x² + 4x - 12
f(2) = (2)² + 4(2) - 12
f(2) = 4 + 8 - 12
f(2) = 12 - 12
f(2) = 0

The vertex of the function is (2,0).

7 0

3 years ago

The division algorithm states that if p(x) and d(x) are polynomial functions with d left parenthesis x right parenthesis not e

katrin [286]

Answer:

In a division algorithm, $p(x)$ refers to the dividend polynomial, $d(x)$ refers to the divisor polynomial, $q(x)$ refers to the quotient polynomial and $r(x)$ refers to the residula polynomial.

The division algorithm is defined as

$p(x)=d(x) \times q(x) +r(x)$

Where $p(x)\geq d(x)$ and $d(x) \neq 0$ , other wise the algorithm won't be defined.

So, the complete paragraph is: "if $p(x)$ and $d(x)$ are polynomial functions with $d(x)\neq 0$ and the degree of $d(x)$ is less than or equal to the degree of $p(x)$ , then there exist unique polynomial functions $q(x)$ and $r(x)$ such that $p(x)=d(x) \times q(x) +r(x)$ .

7 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form for the line that is parallel to the given line and that passes through the given poin

Mamont248 [21]

Y=3x+4 is the equation you are looking for!

8 0

3 years ago

Find the missing angles

lora16 [44]

Let's find a.

We are given a right angle which is 90° and an angle marked by "a" next to it. We know that when they are added together, they make a supplementary angle so we can make a equationa and solve.

90 + a = 180

a = 90°

Let's find b.

By looking at the graph, we can tell that the angle "b" and the angle that measures 163° is the same. Thus, b = 163°.

Let's find c.

Using what we did for a, we can solve for c using what we got for b. We can make an equation and solve.

163 + b = 180

c = 27°

Let's find d.

Using the angle that measures 70°, we can solve it like we did with a and c.

70 + d = 180

d = 110°

Let's find e.

Now that we know what d equals, we know that d and e make a supplmentary angle. So, make an equation and solve.

110 + e = 180

e = 70°

Best of Luck!

5 0

2 years ago