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Marat540 [252]
3 years ago
15

At one point during the hike, Noe is at an elevation of 453 feet. After descending at a rate of 50 feet per

Mathematics
1 answer:
Hoochie [10]3 years ago
4 0

Answer:

6.14 minutes   or   6 minutes & 8.4 seconds

Step-by-step explanation:

Initial elevation: 453 ft

Final elevation: 146 ft

Difference in elevation: 453 ft - 146 ft = 307 ft

speed = 50 ft/min

speed = distance/time

time * speed = distance

time = distance/speed

time = (307 ft)/(50 ft/min)

time = 6.14 minutes = 6 minutes + 0.14 * 60 seconds

time = 6.14 minutes = 6 minutes + 8.4 seconds

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100 POINTS+BRAINLIEST 8TH GRADE MATH PT 4: this one is similar to #3
djverab [1.8K]

Answer:

b.  x + (x + 2) + (x + 4) = 39

Step-by-step explanation:

<u>Definitions</u>

  • Integer:  a whole number that can be positive, negative or zero.
    e.g. ..., -3, -2, -1, 0, 1, 2, 3, ...
  • Odd number: an integer that when divided by two leaves a remainder (so not a multiple of 2).  For example, 1, 3, 5, 7 are all positive odd numbers.
  • Consecutive: following one after the other in order.

<u>The sum of three consecutive odd integers</u>

Let x be the first odd integer.

As there is a <u>difference of 2</u> between <u>consecutive odd integers</u>, the next odd integer after x will be (x + 2).

Therefore, the next odd integer after (x + 2) will be (x + 2) + 2 = (x + 4).

So "the sum of three consecutive odd integers is thirty-nine" is:

x + (x + 2) + (x + 4) = 39

<u>To solve</u>

⇒ x + (x + 2) + (x + 4) = 39

⇒ x + x + 2 + x + 4 = 39

⇒ 3x + 6 = 39

⇒ 3x = 33

⇒ x = 11

Therefore, the three consecutive odd numbers are 11, 13 and 15.

6 0
1 year ago
Read 2 more answers
how do you find the volume of a cylinder describe which measurements of the cylinder you need to know
kvv77 [185]

Answer:

To calculate the volume of a cylinder, you need to know its height and the area of its base. Because a cylinder is a flat-top figure (a solid with two congruent, parallel bases), the base can be either the top or bottom

Step-by-step explanation:

6 0
2 years ago
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The height of a ball thrown into the air after t seconds have elapsed is h = −16t2 + 40t + 6 feet. What is the first time, t, wh
sp2606 [1]
<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>The height of a ball thrown into the air after t seconds have elapsed is:</u></em>

h = -16t^2 + 40t + 6

<em><u>What is the first time, t, when the ball will reach a height of 20 feet?</u></em>

Substitute h = 20

20 = -16t^2 + 40t + 6\\\\-16t^2 + 40t + 6 -20 = 0\\\\-16t^2 + 40t -14 = 0\\\\16t^2 -40t + 14 = 0\\\\8t^2 -20t + 7=0

<em><u>Solve by quadractic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=8,\:b=-20,\:c=7

t = \frac{-\left(-20\right)\pm \sqrt{\left(-20\right)^2-4\cdot \:8\cdot \:7}}{2\cdot \:8}\\\\t = \frac{20 \pm \sqrt{176}}{16}\\\\t = \frac{20 \pm 4\sqrt{11}}{16}\\\\t = \frac{ 5 \pm \sqrt{11}}{4}\\\\We\ have\ two\ solutions\\\\ t=2.07915, \:t=0.42084

Rounding off we get,

t = 2.08 , t = 0.42

Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds

4 0
3 years ago
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son4ous [18]
   8       44
----- = -----
  11      x

8*x=484
/8     /8
=60.5
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3 years ago
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vampirchik [111]

Answer:

Step-by-step explanation:

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5 0
3 years ago
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