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3 years ago

15

Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through

the system is (5.772 - 5.323i) milliamperes (mA). The impedance (Z) in that same system is (3.342 + 4.176i) kilohms (kΩ). Please tell me the magnitude of the voltage in the circuit.

1 answer:

vredina [299]3 years ago

7 0

Answer:Magnitude of voltage is 41.9963 volts

Step-by-step explanation:

Given that current I =5.772-5.323i mA

and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

$=(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}$

$V=(5.772-5.323i)X(3.342+4.176i)$

$V=19.290024+24.103872i-17.789466i-23..5148848i^{2}$

$V=41.518892+6.314406i$

Magnitude of V = $\sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts$

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Answer:

Average weight of the bags of potatoes is 3.8 pounds.

Step-by-step explanation:

Given:

Weight of the first bag, $W_{1}=2.6$ pounds.

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Weight of the third bag is 0.6 pounds more than that of the first bag. This means,

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3 years ago

Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr

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Step-by-step explanation:

step 1

Find the measure of side c

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substitute the given values

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Find the measure of angle A

Applying the law of sine

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}$

$sin(A)=(74)sin(98\°)/76.3$

$A=arcsin((74)sin(98\°)/76.3)$

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Find the measure of angle B

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The sum of the internal angles of a triangle must be equal to 180 degrees

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