Question

Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through the system is (5.772 - 5.323i) milliamperes (mA). The impedance (Z) in that same system is (3.342 + 4.176i) kilohms (kΩ). Please tell me the magnitude of the voltage in the circuit.

Answer 1

Answer:Magnitude of voltage is 41.9963 volts

Step-by-step explanation:

Given that current I =5.772-5.323i mA

          and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

                                            $=(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}$

                                      $V=(5.772-5.323i)X(3.342+4.176i)$

                                      $V=19.290024+24.103872i-17.789466i-23..5148848i^{2}$

                                     $V=41.518892+6.314406i$

Magnitude of V = $\sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts$