Answer:
For both sets of data, the median is equal to the mean.
The interquartile range (IQR) is greater for M's classes than J's classes.
Step-by-step explanation:
<u>J's Classes:</u>
23, 25, 27, 28, 32
Median: 27
Mean: 27
Mean Absolute Deviation: 2.4
Interquartile Range: 3
<u>M's Classes:</u>
20, 24, 26, 29, 31
Median: 26
Mean: 26
Mean Absolute Deviation: 3.2
Interquartile Range: 5
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]

From the given set of conditions, it's likely that you are asked to find the values of

and

at the point

.
By the chain rule, the partial derivative with respect to

is

and so at the point

, we have


Similarly, the partial derivative with respect to

would be found via

Answer:
22 4/5 yards
Step-by-step explanation:
(7 3/5) x 3 = 22 4/5
Answer:
I think it is 49, 96, 400 if you're multiplying
Answer:
y = 1 - x
Step-by-step explanation:
9x + 9y = 9 ( divide through by 9 )
x + y = 1 ( subtract x from both sides )
y = 1 - x