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Alekssandra [29.7K]
3 years ago
5

how many wall are there in your room? what are the shape of the floor and ceiling in your room ? how can you find the area of ea

ch shape?prepare the answer. present the conclusion in the form of report. plz answer the question in right.​
Mathematics
1 answer:
Triss [41]3 years ago
7 0

My room is made up of four walls, both the floor and the ceiling are rectangular in shape.

  • There are four walls in my room.
  • The shape of the floor is a rectangle and given that the ceiling is the same form above the floor, it is also shaped as a rectangle.

To get the area of a rectangle, you use this formula since my floor and ceiling are rectangle.

Area = L * W

where

L = length

W= width

But if you have a square floor and ceiling, the area of a square is

Area = s²

given that it is side * side.

<em>In conclusion, there are </em><em>4 walls</em><em> in every room. The shape of the ceiling or floor could be a </em><em>rectangle or a square</em><em>. It depends on your room and its measurements. To get the area, </em><em>multiply </em><em>the length by the width.</em>

<em>read more at brainly.com/question/24359958?referrer=searchResults</em>

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One leg of a right triangle is 21 inches longer than the other leg, and the hypotenuse is 39 inches.
Valentin [98]

Answer:

One leg - 15 inches

Second leg - 36 inches.

Step-by-step explanation:

One leg - x inches.

Second leg - (x + 21) inches.

Hypotenuse - 39 inches.

Using Pythagorean theorem

x² + (x + 21)² = 39²

x² + x² + 2*21x  + 21² = 39²

2x² + 42x - 39² + 21² = 0

2x² + 42x - 1080 = 0

x² + 21x - 540 = 0

(x - 15)(x + 36) = 0

x = 15, x = - 36

We can use only positive value.

One leg - x inches = 15 inches

Second leg - (x + 21) inches = 15+21=36 inches.

4 0
3 years ago
Jeannie is an experienced business traveler, often traveling back and forth from San Francisco to the East Coast several times p
lesya692 [45]

Answer:

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Jeannie should leave her office 55 minutes early.

Step-by-step explanation:

Let <em>X</em> = time it requires Jeannie to catch her plane.

The random variable <em>X</em> is normally distributed, N(46, 5).

Compute the probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour as follows:

P(X>60)=P(\frac{X-\mu}{\sigma} >\frac{60-46}{5} )\\=P(Z>2.8)\\=1-P(Z

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Now, it is provided that Jeannie has 96% chance of catching her flight if she reaches under <em>x</em> minutes.

That is, P (X < x) = 0.96.

Compute the value of <em>x</em> as follows:

P(X

**Use the <em>z</em>-table to compute the value of <em>z</em>.

The value of <em>z</em> is 1.751.

Compute the value of <em>x</em> as follows:

z=\frac{x-46}{5}\\ 1.751=\frac{x-46}{5}\\x=46+(1.751\times5)\\=54.755\\\approx 55

Thus, Jeannie should leave her office 55 minutes early.

4 0
3 years ago
Can somebody help me please
Strike441 [17]

Answer:

35m

Explanation:

Perimeter is the sum of all the sides of a shape, or a+b+c=P.

12m+8m+15m = 35m

7 0
3 years ago
Read 2 more answers
Plz help ill mark u brainliest and 25 pts
Ahat [919]

Answer:

B

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
2 years ago
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