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victus00 [196]
4 years ago
9

Mr. Smith and his wife were trying to move their new chair. Mr. Smith pulls with a force of 30 N while Mrs. Smith pushes with a

force of 25 N in the same direction. What is the net force?
Physics
1 answer:
STALIN [3.7K]4 years ago
4 0

The Answer: 55 N

Reason: Because they are pushing in the same direction, their force of N gets added.

1. 30 + 25 = 55

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An electric field of 8.20 ✕ 105 V/m is desired between two parallel plates, each of area 25.0 cm2 and separated by 2.45 mm. Ther
astraxan [27]

Answer:

q = 1.815 \times 10^{-8} C

Charge on one plate is positive in nature and on the other plate it is negative in nature.

Explanation:

E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm

According to the Gauss's theorem in electrostatics

The electric field between the two plates

E = \frac{\sigma }{\varepsilon _{0}}

{\sigma }= E \times {\varepsilon _{0}}

{\sigma }= 8.20 \times 10^{5} \times {8.854 \times 10^{-12}

{\sigma }= 7.26 \times 10^{-6} C/m^{2}

Charge, q = surface charge density x area

q = 7.26 \times 10^{-6} \times 25 \times 10^{-4}

q = 1.815 \times 10^{-8} C

5 0
3 years ago
Compare the work done by the electrical field when the particle travels
Svetach [21]
Show transcribed image text. Compare the work done by the electric field when the particle travels<span> from point W to point X to that </span>done<span> when the </span>particle travels<span> from point Z to point Y. ... Is the </span>work done<span> on the </span>particle<span> by the </span>electric field<span> positive, negative, or zero? Explain using force and displacement vectors.</span>
4 0
4 years ago
The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object
Gennadij [26K]
Given:
Focal length: 5.0 cm
image produced: -10.0 cm

mirror equation:   1/di + 1/do = 1/f

Look for the actual distance of the object from the mirror. Solve for do.

1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do

The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.
3 0
4 years ago
Read 2 more answers
A pulley with a radius of 3.0 cm and a rotational inertia of 4.5 x 10^-3 kg∙m2 is suspended from the ceiling. A rope passes over
solmaris [256]

Answer:

maximum kinetic energy is for Pulley

e) The pulley

Explanation:

Let 4 kg block is moving downwards with speed "v" so we can say that 2 kg block will move upwards with same speed "v"

Now we know that pulling is in pure rotational motion

so we will have

\omega = \frac{v}{R}

\omega = \frac{v}{0.03}

now kinetic energy of each is given as

For 4 kg block

K_1 = \frac{1}{2}(4)(v^2) = 2v^2

for 2 kg block

K_2 = \frac{1}{2}(2)(v^2) = v^2

For pulley

K_3 = \frac{1}{2}I\omega^2

K_3 = \frac{1}{2}(4.5\times 10^{-3})\frac{(v^2)}{0.03^2}

K_3 = 2.5 v^2

So maximum kinetic energy is for Pulley

3 0
3 years ago
an object sinks to the bottom of a container filled with water.what is the relationship between the weight of the object and the
mars1129 [50]
If the object sinks, then it must be heavier than the weight of the water
it displaces ... heavier than the buoyant force acting on it. 

If the buoyant force were equal or greater than the object's weight, then
the object would rise to the surface in water.
6 0
3 years ago
Read 2 more answers
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