Why should the lock and key be gay?
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The rotational equilibrium condition allows finding the response to the minimum force of the wind and what happens when changing the water for sand, in the system
a) The minimum force of the wind that turns the system is Fw = 17.64 N
b) The system resists much greater forces because the base has more mass
Newton's Second Law can be applied to rotational motion in this case when the angular acceleration is zero we have the special case of rotational equilibrium
Σ τ = 0
Where τ is the torque
The reference system is a coordinate system with respect to which the torques are measured, in this case we will fix the system at the turning point, the junction of the base and the pole, we will assume that the counterclockwise rotations are positive.
For the torque the distance used is the perpendicular distance from the direction of the force to the axis of rotation, let's find this distance for each force
Wind force
cos 15 =
= 2.35 cos 15
Post Weight
sin 15 =
xp = 2.0 sin 15
Base weight
cos (90-15) =
xB = 0.25 cos 75
Let's substitute in the rotational equilibrium equation
a) To calculate the minimum wind force we substitute the given values
They indicate the weight of the post is = 26.0 N and the weight of the base with water is
= 810 N
Let's calculate
= 17.64 N
b) The water is exchanged for sand.
In this case, as the density of the sand is greater than that of the water, the base will have more weight, so it will resist stronger winds before turning over.
Using the rotational equilibrium condition we can find the response to the minimum force of the wind and what happens when changing the water for sand,
a) the minimum force of the wind that turns the system is Fw = 17.64 N
b) the system resists much greater forces because the base has more mass
Learn more here: brainly.com/question/7031958
a) 779 kg m/s
The momentum of an object is given by:
p = mv
where
m is the mass of the object
v is its velocity
For the fullback before the collision,
m = 95 kg
v = 8.2 m/s
Therefore, his momentum was:
b) -779 kg m/s
After the collision, both the fullback and the tackle come to a stop: this means that their momentum after the collision is zero,
p' = 0
The initial momentum of the fullback was
p = 779 kg m/s
Therefore, his change in momentum is
where the negative sign indicates that the direction is opposite to the initial direction of motion.
c) -779 kg m/s
Here we can apply the law of conservation of momentum. In fact, the total momentum before and after the collision must be conserved. So we can write:
where
is the initial momentum of the fullback
is the initial momentum of the tackle
p' is the final combined momentum after the collision
We already know that
Therefore, we can find the tackle's original momentum:
where the negative sign indicates that the direction is opposite to the initial direction of motion of the fullback.
e) -6.1 m/s
To find the velocity of the tackle, we can use again the equation of the momentum:
p = mv
where here we have
is the original momentum of the tackle
m = 128 kg is his mass
Solving the equation for v, we find the tackle's original velocity:
So, he was moving at 6.1 m/s in the direction opposite to the fullback.