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3 years ago

If the wind or current is pushing your boat away from the dock as you prepare to dock, which line should you secure first?

Physics

1 answer:

Akimi4 [234]3 years ago

7 0

Answer:

Bow Line

Explanation:

If the wind or current is pushing your boat away from the dock, bow line should be secured first.

1- We should cast off the bow and stern lines.

2-With the help of an oar or boat hook, keep the boat clear of the dock.

3-Leave the boat on its own for sometime and let the wind or current carry the boat away from the dock.

4 - As you see there is sufficient clearance, shift into forward gear and slowly leave the area.

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A 0.060-kg ice hockey puck comes toward a player with a high speed. The player hits it directly back softly with an average forc

kramer

Answer:u=-22 m/s

Explanation:

Given

mass of puck $m=0.06\ kg$

Average force $f_{avg}=1.5\times 10^3\ N$

time of contact $t=1.2ms=1.2\times 10^{-3}\ s$

puck leaves with a velocity of $v=8\ m/s$

We know impulse is $F_{avg}\Delta t$ $=\text{change in momentum}$

therefore

$1.5\times 10^3\times (1.2\times 10^{-3})=P_f-P_i$

$P_i=0.06\times 8-1.8$

$P_i=0.48-1.8=-1.32\ kg-m/s$

Final momentum $P_f=m\times v_f$

$P_f=0.06\times 8$

$P_f=0.48\ kg-m/s$

Impulse on the ball $=F_{avg}\Delta t$

Impulse $=1.5\times 10^3\times 1.2\times 10^{-3}=1.8\ N-s$

Initial velocity is given by

$u=\frac{P_i}{m}=\frac{-1.32}{0.06}$

$u=-22\ m/s$

i.e. initially ball is moving towards -x-axis

8 0

3 years ago

Consider the concepts of kinetic energy (KE) and gravitational potential energy (GPE) as you complete these questions. A ball is

Lena [83]

Answer:

When the ball is held motionless above the floor, the ball possesses only GPE energy.If the ball is dropped, its GPE energy decreases as it falls.If the ball is dropped, its KE energy increases as it falls.

Explanation:

If the ball is held motionless, then its kinetic energy is equal to zero, since kinetic energy depends on the velocity. And the ball is held above the ground, which means it possesses gravitational potential energy.

If the ball is dropped, its height will decrease, therefore its gravitational potential energy will decrease. Along the way, the ball will be in free fall, and therefore its velocity will increase, hence its kinetic energy.

$K = \frac{1}{2}mv^2\\U = mgh$

3 0

3 years ago

Saturn’s rings are composed of __________.

sineoko [7]

Answer:

Explanation:

8 0

3 years ago

Read 2 more answers

What is the purpose of heat index

Nookie1986 [14]

<span>It tells how hot it really feels when the relative humidity is factored in with the actual air temperature.
hope this helps</span>

7 0

3 years ago

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A ball is thrown so that its initial vertical and horizontal components of velocity are 30 m/s and 15 m/s, respectively. Estimat

mihalych1998 [28]

Answer:

H = 45 m

Explanation:

First we find the launch velocity of the ball by using the following formula:

v₀ = √(v₀ₓ² + v₀y²)

where,

v₀ = launching velocity = ?

v₀ₓ = Horizontal Component of Launch Velocity = 15 m/s

v₀y = Vertical Component of Launch Velocity = 30 m/s

Therefore,

v₀ = √[(15 m/s)² + (30 m/s)²]

v₀ = 33.54 m/s

Now, we find the launch angle of the ball by using the following formula:

θ = tan⁻¹ (v₀y/v₀ₓ)

θ = tan⁻¹ (30/15)

θ = tan⁻¹ (2)

θ = 63.43°

Now, the maximum height attained by the ball is given by the formula:

H = (v₀² Sin² θ)/2g

H = (33.54 m/s)² (Sin² 63.43°)/2(10 m/s²)

6 0

3 years ago