9514 1404 393
Answer:
- see below for a sketch
- 12 km
Step-by-step explanation:
The distance can be calculated using the Law of Cosines. The angle internal to the triangle at Q is (180°-(146° -65°)) = 99°. Then the distance PR can be found from ...
PR² = PQ² +QR² -2·PQ·QR·cos(∠PQR)
PR² = 6² +10² -2·6·10·cos(99°) ≈ 154.77
PR ≈ √154.77 ≈ 12.44 . . . . km
The distance PR is about 12 km.
Answer:
12
Step-by-step explanation:
B
C
=
16.17
(
2
d
p
)
c
m
Explanation:
In triangle ABC, side
A
C
=
15
, Angles are
∠
B
=
68
0
;
∠
C
=
24
0
and
∠
A
=
180
−
(
68
+
24
)
=
88
0
We know by sine law
A
C
sin
B
=
B
C
sin
A
or
15
sin
68
=
B
C
sin
88
or
B
C
=
15
⋅
sin
88
sin
68
=
16.17
(
2
d
p
)
c
m
Step-by-step explanation:
Answer:
Step-by-step explanation:
817
x 45
_______
+ 4085
+ 32680
__________
36,765