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pogonyaev
3 years ago
12

In a list of five consecutive odd integers, the sum of the first and double the last is 139. What is the largest sum?

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

Answer: 49

Step-by-step explanation:

From your question, I think you mean the largest number. The answer is given below.

Let the five consecutive odd numbers be:

a, a+2, a+4, a+6 and a+8.

Thee sum of the first and double the last is 139. This can be written as:

a + 2(a+8) = 139

a + 2a + 16 = 139

3a + 16 = 139

3a = 139 - 16

3a = 123

a = 123/3

a = 41

The first number = 41

The largest number = a+8 = 41 + 8 = 49.

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Basile [38]
The answer to this problem is the letter "A" which is "Multiply by 3, then add 2"
and can be written a N = 3n + 2
At first, we have initial value such n = 1
Then the second value is:
N = 3*1 + 2
N = 5
The third value is:
N = 3*5 + 2
N=17
The next values are:
N = 3*17 + 2
N= 53
The letter "A" is the inductive reasoning to the given sequence.
6 0
3 years ago
Is 23 and 25 co-primes
MariettaO [177]

Answer:

yes because they have one as a company factor

7 0
3 years ago
56 points for whoever answers correctly !
vladimir2022 [97]

We need to use what we know about rectangles to get:

1)

  • Total length = 2*W + 8ft
  • Total width = W + 8ft

2) area = 2*W^2 + 24ft*W + 64ft^2

<h3>Working with rectangles:</h3>

We know that rectangles are defined by two measures, width W and length L.

Here we do know that the length of the pool is twice the width, and the width is W, then the length of the pool is:

L = 2*W

And we also have a sidewalk of 4ft all around the pool, now we want to get:

1) The total length and the total width.

This will be equal to the length/width of the pool <u>plus twice the width of the sidewalk</u> (we add it twice because is in both ends) then we have:

  • Total length = L + 2*4ft = 2*W + 8ft
  • Total width = W + 2*4ft = W + 8ft

2) Now we want to get an expression for the total area of the pool.

Remember that for a rectangle the area is just the product between the width and the length, so to get the area of the pool with the sidewalk we just take:

area = (total length)*(total width)

area = (2*W + 8ft)*(W + 8ft) = 2*W^2 + 3*W*8ft + 64ft^2

area = 2*W^2 + 24ft*W + 64ft^2

This is the equation that gives the total area as a function of W, the width of the pool.

If you want to learn more about rectangles, you can read:

brainly.com/question/17297081

6 0
2 years ago
Find the area of a circle with a radius of 21 feet. Use 22/7 for pi.
shusha [124]

Answer:

1386 square units

Step-by-step explanation:

Area of a cirlce = Pi x r^2 [ Pi is 22/7 as stated in question]

22/7 x 21^2 = 1386 sq. units

5 0
3 years ago
2. Consider the circle x² + y2 = 1, given in figure. Let OP makes an angle 30° with the x axis.
PolarNik [594]

The equation of the tangent line to the circle passing through the point P is; y = (1/√3)x ± 2/√3

<h3>How to find the equation of the tangent?</h3>

I) We are given the equation of the circle as;

x² + y² = 1

Since angle of inclination is 30°, then slope is;

m = tan 30 = 1/√3

Then equation of the tangent will be;

y = (1/√3)x + c

Put  (√3)x + c into the given circle equation to get;

x² + ((1/√3)x + c)² = 1

x² + ¹/₃x² +  (2/√3)cx + c² = 1

⁴/₃x² +  (2/√3)x + (c² - 1) = 0

Since we need to find value of c for equation to become tangent, then the above quadratic equation must have real and equal roots.

Thus;

((2/√3)c)² - 4(⁴/₃)(c² - 1) = 0

⁴/₃c² - ¹⁶/₃(c² - 1) = 0

⁴/₃c² - ¹⁶/₃c² + ¹⁶/₃ = 0

4c² = ¹⁶/₃

c² = ⁴/₃

c = √⁴/₃

c = ±²/√3

Thus, equation of tangent is;

y = (1/√3)x ± 2/√3

II) Radius from the given equation is 1. Thus, we will use trigonometric ratio to find the x and y intercept;

x-intercept is at y = 0;

0 = (1/√3)x ± 2/√3

-(1/√3)x = ±2/√3

Intercept is positive. Thus;

x = (2/√3)/(1/√3)

x = 1

y - intercept is positive at x = 0;

y = (1/√3)0 ± 2/√3

y = 2/√3

Read more about Equation of tangent at; brainly.com/question/17040970

#SPJ1

6 0
1 year ago
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