Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
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48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
54: 1, 2, 3, 6, 9, 18, 27, 54
gcf: 6
Answer:
-4x+5
Step-by-step explanation:
use FOIL
Answer:
The amount invested in CDs is $1,340
The amount invested in the stock portafolio is $6,900
The amount invested in the saving accounts is $2,300
Step-by-step explanation:
Let
x ---->the amount invested in CDs at 2.1%
y ---> the amount invested in the stock portfolio at 2.5%
z ---> the amount invested in the savings account at 1.5%
----> equation A
----> equation B
substitute equation B in equation A
----> equation C
we know that
The total interest earned by the three amount must be equal to $231.69
so
----> equation D
substitute equation B and equation C in equation D
solve for y
<em>Find the value of x</em>
<em>Find the value of z</em>
