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Usimov [2.4K]
4 years ago
15

Solve the given equation on the domain [0,2π]: 2sinx-sqrt(2)=0sqrt=squareroot

Mathematics
1 answer:
kiruha [24]4 years ago
3 0
2 sin(x) - √2 = 0

2 sin(x) = √2

sin(x) = (1/2) √2

x = sin⁻¹ ( 1/2 √2 ) = <u>45°</u> and <u>135°</u> .
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