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Usimov [2.4K]
4 years ago
15

Solve the given equation on the domain [0,2π]: 2sinx-sqrt(2)=0sqrt=squareroot

Mathematics
1 answer:
kiruha [24]4 years ago
3 0
2 sin(x) - √2 = 0

2 sin(x) = √2

sin(x) = (1/2) √2

x = sin⁻¹ ( 1/2 √2 ) = <u>45°</u> and <u>135°</u> .
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*****50 POINTSSSS*****
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Answer:

<h3>Given</h3>
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<h3>Solution</h3>
  • m∠GAR = 180° - m∠REG = 180° - 78° = 102° (supplementary angles sum to 180°)
  • m∠TAR = 1/2mAR = 1/2(46°) = 23°   (tangent chord angle is half the size of intercepted arc)
  • m∠GAN = 180° - (m∠TAR + m∠GAR) = 180° - (23° + 102°) = 55° (straight angle is 180°)
  • mAG = 2m∠GAN = 2(55°) = 110°
  • mRE = mAG = 110° (as ER ≅ GA)
  • mGE = 360° - (mAG + mAR + mRE) = 360° - (110° + 46° + 110°) = 94° (full circle is 360°)
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