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Mathematics

1 answer:

vova2212 [387]3 years ago

4 0

Answer:

RT = 9

Step-by-step explanation:

x-2 + 4x-9 = x+5

5x-11 = x+5

subtract the x from the right side to 5x and the left side x cancels out

add 11 on the right side which cancels out and add to right side

4x = 16

divide 4x by 4 which cancels out and divide 16 by 4

x = 4

take the equation for RT = x+5

yk x = 4 so that makes 4+5 which is equal to 9

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Y = 5x + 7<br> 2x + y = -5<br> Are the equations parallel,<br> perpendicular, or neither?

Nezavi [6.7K]

Lines are neither perpendicular nor parallel.

Step-by-step explanation:

Step 1:

In equation 1, Y = 5X + 7

In equation 2, Y = -2X -5

Step 2:

Slope Intercept form Y =mX +c

Where m = Slope

Slope of line 1 = 5

Slope of line 2 = -2

m1 is not equal to m2. Hence it is not parallel.

m1 × m2 is not equal to -1. Hence they are not perpendicular.

3 0

3 years ago

Answer Question number 5 <br> Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$