Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99
Step-by-step explanation: Ok, so let's put the data set from least to greatest....
(63, 63, 76,) (77, 79,) (84, 99, 99)
First Quartile Third Quartile
First, let's find the median, since you made a little mistake...
77 + 79 = 156
156 ÷ 2 = 78
The median is 78!
Now, let's determine the first quartile and the third quartile.
For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...
First Quartile: 63
Third Quartile: 99
I hope this helps!
Answer:
6j + 6r :)))))))))))))))))
Answer:
0.00000381469
Step-by-step explanation:
there u go
Answer:
Option A.
Step-by-step explanation:
The given matrix is
We need to find the system of equations which is represented by the matrix.
In the given matrix first row represents the first equation and second row represents the second equation of the system of equations.
Let two variables are x and y.
First column represents the coefficients of x and second column represents the coefficients of y.
Numbers on the right side of the matrix represents the numbers which are right side of the equations.
Now, the required equations are
Therefore, the correct option is A.