All categories

2 years ago

Need help on this plzz

Mathematics

1 answer:

Aleksandr [31]2 years ago

5 0

I do believe that it's one of the bisected ones. bisect is the line that splits the middle and D is definitely wrong. So that should narrow it down. So I would go with A or B. Sorry if I didn't help much but it's better than having no clue.

You might be interested in

How do you factor 33x^5y^2+21x^3y+9x^3y^3?

scZoUnD [109]

Answer:

3x³y(11x²y+3y²+7)

Step-by-step explanation:

hope that helps

7 0

3 years ago

Please help quickkkkkkk

Paraphin [41]

Y=2 since its going straight through the y axis at the point 2

3 0

2 years ago

Read 2 more answers

How many liters will a U.S. 6-quart container hold? Round your answer to the nearest hundredth

vovikov84 [41]

You are given volume of 6 US quart. You are required to convert this into liters and be rounded off to the nearest hundredth. Keep in mind that for volume, every one liter is equal to 1.05669 US quart. So you need to divide the 6 US quart. This is equal to 6.34014 liters. To round of the nearest hundredth, the ocation of the hundredth is the four in 6.34014. since after four is zero, the round off rule states that from 0-4, the preceding number remains unchanged. So the final answer is 6.34 liters.

8 0

3 years ago

Read 2 more answers

What’s the circumference, to this problem ?

Dafna11 [192]

Answer:

The formula to get the circumference of a circle is $C=2*\pi * r$ but in this case we see that a diameter is being used therefore we can get rid of the 2 and the r because that is what the diameter and just replace d into there like this $C=d*\pi$ .

We can then input the value and we get that $C=1*\pi$ which then just narrows down to $C=3.142$ .

Hope this helps! Let me know if you have any questions

7 0

2 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago