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harina [27]
2 years ago
7

Assume the given distributions are normal. Cucumbers grown on a certain farm have weights with a standard deviation of 2 ounces.

What is the mean weight if 85% of the cucumbers weigh less than 16 ounces?Assume the given distributions are normal.Group of answer choices14.4014.3014.8813.92
Mathematics
1 answer:
forsale [732]2 years ago
4 0

Answer:

13.92

Step-by-step explanation:

We have that the critical z-score associated with 85% to the left is 1.04, we know that by table.

So we have to:

m + z * (sd) = 16

where m is the mean, z is the critical z-scor and sd is the standard deviation, if we replace we are left with:

m + 1.04 * (2) = 16

m = 16 - 1.04 * (2)

m = 13.92

Therefore, the average weight if 85% of cucumbers weigh less than 16 ounces is 13.92

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Answer:

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Hope this helps!

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asambeis [7]

Answer

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Step by step explanation

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Similarly,

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8 0
3 years ago
Which of the lines graphed in the diagram represents the equation 6x + 4y = 8
Blizzard [7]
In order to easily discern which graph is a proper representation of 6x + 4y = 8, you first need to convert the equation to y = mx+ b, also known as slope-intercept form. Here's how you can do this:
6x + 4y = 8
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y = -1.5x + 2
The +2 tells you that your line will intercept the vertical y-axis at (0, 2). This narrows it down to graphs a and d. Then, because you have a NEGATIVE number in front of your x (it's -1.5), you can tell that your graph will be going down as it moves from left to right. This leaves you with graph d as your answer!
6 0
2 years ago
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Can someone help pls 18-3 X 2/5-1^2
d1i1m1o1n [39]

Answer:

3

Step-by-step explanation:

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Mandarinka [93]

Answer:

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Given the expression

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